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Gelneren [198K]
2 years ago
5

What is the slope of the line that passes through (4,1) and (7,-2)?

Mathematics
1 answer:
Alenkinab [10]2 years ago
5 0
Slope formula;
m = y2 - y1/ x2 - x1                     point(x, y) = (4, 1), (7, -2)
 
m = -2 - 1/ 7 - 4
m = -3/3
m = -1

the slope is -1.

hope this helps, God bless!
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The perimeter of a kite is 51 meters. If one side measures 18 meters find the measure of the opposite side.
puteri [66]
Let n and m be the sides of the kite
perimeter = 2(m+n)
51 = 2(18+m)
51/2 = 18 + m
25.5 - 18 = m
m = 7.5m
4 0
2 years ago
2. A fair dice is rolled. What is the probability that a number divisible by 3 is rolled?
Anni [7]

Answer: 2

Step-by-step explanation:

A dice has 6 numbers on it, 1,2,3,4,5, and 6.

how many pairs of 3 can you make?

(1   2   3)   (4   5   6)

There are 2 pairs, so your answer is 2

6 0
3 years ago
A system of equations is given below. y=1/2x-3 and -1/2x-3. Which of the following statements best describes the two lines?
pantera1 [17]

"They have different slopes but the same y-intercept, so they have one solution" is the statement which best describes the two lines.

Answer: Option D

<u>Step-by-step explanation:</u>

Given equations:

           y=\left(\frac{1}{2} \times x\right)-3

           y=\left(-\frac{1}{2} \times x\right)-3

As we know that the slope intercept form of a line is  

                             y = m x + c  

So, from equation 1 and equation 2 we can see that

              m_{1}=\frac{1}{2} \quad \text { and } c_{1}=-3

              m_{2}=-\frac{1}{2} \text { and } c_{2}=-3

So, from the above expressions, we can say that both lines have different slopes but have same y – intercept with one common solution when x = 0.

4 0
3 years ago
Read 2 more answers
A person gets on and off a bathroom scale four times. The four readings (in pounds) are 148, 151, 150, and 152. Each time after
Ganezh [65]

Answer:

See explanation below

Step-by-step explanation:

Since each time after the person gets off the scale, the reading is 2 lb the person's weight must be near the mean of

148-2, 151-2, 150-2, 152-2; that is to say, near the mean of 146, 149, 148, 150 = (146+149+148+150)/4 = 148.25

We could estimate the uncertainty as <em>the standard error SE </em>

\bf SE=\frac{s}{\sqrt{n}}  

where  

<em>s = standard deviation of the sample </em>

<em>n = 4 sample size. </em>

Computing s:

\bf s=\sqrt{\frac{(146-148.25)^2+(149-148.25)^2+(148-148.25)^2+(150-148.25)^2}{4}}=1.479

So, the uncertainty is 1.479/2 = 0.736

<em>It is not possible to estimate the bias, since it is the difference between the true weight and the mean, but we do not know the true weight. </em>

5 0
2 years ago
Is this a proportional relationship? Please help!
OLEGan [10]

Answer:

No

Step-by-step explanation:

If you draw a line, it will not go through the origin and there isn't a constant rate of change.

6 0
1 year ago
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