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liubo4ka [24]
4 years ago
8

The pyramid shown has a square base that is 12 centimeters on each side. The slant height is 18 centimeters. What is the surface

area of the pyramid?
Mathematics
2 answers:
amid [387]4 years ago
6 0

Answer:

576 square meters

Step-by-step explanation:

your welcome

give me brainliest

Lemur [1.5K]4 years ago
3 0
576 because the triangle in the pyramid would be 216 divided by 2 is 108 since there is 4 triangles to a pyramid you multiply by 4 and that is 432. Then you add the area of the square which is 144 and add that to 432 which makes it 576
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Determine the point on the hyperbola −3x2+2y2=10 closest to the point (4, 0).
umka2103 [35]
-3x^2 + 2y^2 = 10
2y^2 = 10 + 3x^2
y^2 = 5 + 3/2x^2

distance between two points is given by
d = sqrt((x2 - x1)^2 + (y2 - y1)^2) = sqrt((x - 4)^2 + (y - 0)^2) = sqrt((x - 4)^2 + y^2) = sqrt((x - 4)^2 + 5 + 3/2x^2)
For d to be minimum (closest), dd/dx = 0
(2(x - 4) + 3x)/2sqrt((x - 4)^2 + 5 + 3/2x^2) = 0
2(x - 4) + 3x = 0
2x - 8 + 3x = 0
5x = 8
x = 8/5 = 1.6

y^2 = 5 + 3/2(1.6)^2 = 5 + 3/2(2.56) = 221/25
y = sqrt(221/25) = 2.97

Therefore, the required point is (1.6, 2.97)
6 0
3 years ago
Evaluate (-32)^-4/5 . Do not leave any exponents in your answer.
Alexeev081 [22]

Answer:

  • 1/16

Step-by-step explanation:

  • (-32)^-4/5 =
  • (-2^5)^-4/5 =
  • (-2)^-(5*4/5) =
  • (-2)^ -4=
  • 16^-1=
  • 1/16
3 0
3 years ago
Sharvay spends $15 to buy 17 pieces of candy. M&M’s cost $0.75 and candy bars cost $1. How many M&M’s and candy bars did
Zinaida [17]

Answer:

8 M&Ms and 9 Candy Bars

Step-by-step explanation:

$15 dollars could buy 15 candy bars, and there are 17 pieces of candy total.

Prioritizing the number of bars:

0.75 * 2 = 1.50

1.50 * 2 = 3

At least $3 were spend on M&Ms, meaning 4 M&Ms and 12 candy bars, which is only 16 candy pieces...

8 M&Ms and 9 candy bars is equivalent to 17 total candy pieces.

8 0
4 years ago
How many faces are glued together?
Rudiy27

Answer:

There are 4 or 8 faces glued together.( it depends how you count

Step-by-step explanation:

if you take a look at the figure you see it consis of a rectangle with for cubs stcked up on one of the ends. This means the glue is in between the four cubs in the base and the stacked cubes. this means there are eight faces that have been attached since each cube is glued by one of their faces.

6 0
3 years ago
Table below shows the age in years and the retail value in thousands of dollars of a random sample of ten automobiles of the sam
horrorfan [7]

Answer:

Step-by-step explanation:

Hello!

Given the study variables

X: Age of an automobile (years)

Y: Retail value of an automobile (thousands of dollars)

a) Construct a scatter diagram.

(attached image)

b) Compute the linear correlation coefficient r. Interpret its value in the context of the problem.

The formula for the correlation coefficient (Person) is:

r= \frac{sum(XY)-\frac{sum(X)*sum(Y)}{n} }{[sum(X^2)-\frac{(sum(X))^2}{n}] * [sum(Y^2)-\frac{(sum(Y))^2}{n} ] }

First you have to do some intermediate summatories:

∑x= 40

∑x²= 174

∑y= 246.30

∑y²= 6154.15

∑xy= 956.5

r= \frac{956.5-\frac{40*246.3}{10} }{[147-\frac{(40)^2}{10}] * [6154.15-\frac{(246.3)^2}{10} ] }

r= -0.818 ≅ 0.82

-0.82 indicates there is a strong negative linear correlation between the age of the automobiles and the retail price. Wich means that the older the car, the less it costs.

c) Compute the least squares regression line. Plot it on the scatter diagram.

Interpret the meaning of the slope of the least-squares regression line in the context of the problem.

The least squares regression line is Y= a + bX

To calculate the regression line you need to calculate the values of "a" and "b"

a= (\frac{sum(Y)}{n} ) -b(\frac{sum(X)}{n} )

a= (\frac{246.3}{10} ) -(-2.05)(\frac{40}{10} )

a= 32.83

b= \frac{sum(XY)-\frac{sum(X)*sum(Y)}{n} }{sum(X^2)-(\frac{sum(X)^2}{n})}

b= \frac{956.5-\frac{40*246.3}{10} }{174-(\frac{40^2}{10})}

b= -2.05

Y= 32.83 - 2.05X

Check attachment for graphic.

-2.05(\frac{years}{thousanfs of dollars}) is the modification of the estimated mean of the retail value of automobiles every time their age increases one year. In other words, every time the automobiles increase their age in one year, the price decreases 2.05 thousands of dollars.

e) Suppose a 20 -year-old automobile of this make and model is selected at random. Use the regression equation to predict its retail value. Interpret the result.

You need to calculate the value of Y for a value of X of 20 years. To do so you replace the values in the regression equation:

Y= 32.83 - 2.05(20)

Y= -8.17 thousands of dollars.

Under the model Y= 32.83 - 2.05X, a 20-year-old automobile has a retail price of -8.17 thousands of dollars.

This is mathematically correct even if it doesn't make sense in context.

f) Comment on the validity of using the regression equation to predict the price of a brand new automobile of this make and model.

You can only use the regression equation to predict possible values of Y for values of X that are between the range of definition of the variable. In this case, the variable is defined in numbers from 2 to 6 years.

You can predict values outside the range of definition of X but the further these values are from the definition range, the less accurate and imprecise the prediction is.

For example in question e) I've predicted the value of Y for X= 20 years, although I've obtained a result truth is that this prediction is not accurate nor reliable.

I hope it helps!

8 0
4 years ago
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