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3 years ago

15

What are different representations of a function?

1 answer:

Soloha48 [4]3 years ago

8 0

Answer:

a function can be represented by a bike

Step-by-step explanation:

a bike has many things that work together to power the bike

the pedals allow the bike to move. the handles allow the bike to move different directions. the wheels allow the bike to move while working withe the pedals and the gears

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2. What is the value of 9x – 4y if x = 3 and y = 2?<br> F. 12.<br> G. 19<br> H. 93<br> 1. 27<br> H

Igoryamba

Answer:

G. 19 is your answer dear

Step-by-step explanation:

9(3)-4(2)

27-8 = 19

3 0

3 years ago

- 3 1/5 + (-6 1/2)<br> A -3 2/7<br> B-3 7/10<br> C-9 2/7<br> D-9 7/10

Lelechka [254]

The answer is D -9 7/10

8 0

3 years ago

Are the two triangles similar? how do you know

Zinaida [17]

I forgot what they’re called but the angles opposite to each other are the same degree. It’s a theorem, just search up the name

7 0

3 years ago

Solution to the system<br> y=-x2-3x+2<br> y=x+6

worty [1.4K]

Answer:

$x=-2,y=4$

Step-by-step explanation:

$y=-x^2-3x+2$

$y=x+6$

$x+6=-x^2-3x+2$

$x^2+x+6=-3x+2$

$x^2+4x+6=2$

$x^2+4x+4=0$

$(x+2)(x+2)=0$

$x=-2$

$y=(-2)+6=4$

8 0

2 years ago

Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

3 0

4 years ago

Read 2 more answers