27 out of 39 win i guess
If u think this is right ok
Step-by-step explanation:
Height of ladder = 12ft .
Here perpendicular is height to which it reaches .
<u>When </u><u>angle </u><u>is </u><u>3</u><u>0</u><u>⁰</u><u> </u><u>:</u><u>-</u>
=> sin 30⁰ = H/12
=> ½ = H/12
=> H = 12/2
=> H = 6m ( ans )
<u>When </u><u>Angle </u><u>is </u><u>4</u><u>5</u><u>⁰</u><u> </u><u>:</u><u>-</u><u> </u>
=> sin45⁰ = H/12
=> 1/√2 = H/12
=> H = 6*√2*√2/√2
=> H = 6√2 m ( ans )
<u>When </u><u>angle</u><u> </u><u>is </u><u>6</u><u>0</u><u>⁰</u><u> </u><u>:</u><u>-</u>
=> sin60⁰ = H/12
=> √3/2 = H/12
=> H = 12 *√3/2
=> H = 6√3 ( ans )
hope it helped !
The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
Learn more about the area of a circle here:
brainly.com/question/15673093
#SPJ1
Answer:
t=5.5080( to 3 d.p)
Step-by-step explanation:
From the data given,
n =20
Deviation= 34/20= 1.7
Standard deviation (sd)= 1.3803(√Deviation)
Standard Error = sd/√n
= 1.3803/V20 = 0.3086
Test statistic is:
t = deviation /SE
= 1.7/0.3086 = 5.5080
ndf = 20 - 1 = 19
alpha = 0.01
One Tailed - Right Side Test
From Table, critical value of t =2.5395
Since the calculated value of t = 5.5080 is greater than critical value of t = 2.5395, the difference is significant. Reject null hypothesis.
t score = 5.5080
ndf = 19
One Tail - Right side Test
By Technology, p - value = 0.000
Since p - value is less than alpha , reject null hypothesis.
Conclusion:
From the result obtained it can be concluded that ,the data support the claim that the mean rating assigned to the wine when the cost is described as $90 is greater than the mean rating assigned to the wine when the cost is described as $10.
<span> C. -8 or 8
</span>
4 |-8| = 4*8 = 32
4 |<span>8</span>| = 4*8 = 32
