Answer:
Y=s^2/36 and y=5.7;14.3 ft
Step-by-step explanation:
The question was not typed correctly. Here, a better version:
<em>The aspect ratio is used when calculating the aerodynamic efficiency of the wing of a plane for a standard wing area, the function A(s)=s^2/36 can be used to find the aspect ratio depending on the wingspan in feet. If one glider has an aspect ratio of 5.7, which system of equations and solution can be used to represent the wingspan of the glider? Round solution to the nearest tenth if necessary. </em>
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</em>
<em>Y=s^2/36 and y=5.7;14.3 ft
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<em>Y=5.7s^2 and y=36; s=2.5ft
</em>
<em>Y=36s^2 and y=0; s=0.4 ft
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<em>Y=s^2/36 +5.7 and y=0; s=5.5 ft</em>
In the function A(s)=s^2/36 A(s) represents the aspect ratio and s the wingspan. If one glider has an aspect ratio of 5.7, then A(s) = 5.7. We want to know the wingspan of the glider. Replacing A(s) by Y we get the following system of equation:
Y=s^2/36
with y = 5.7
5.7 = s^2/36
5.7*36 = s^2
√205.2 = s
14.3 ft
Answer:
sorry
Step-by-step explanation:
i think hope this helps
Step-by-step explanation:
Hi there!
Given;
f(x) = 17x + 9
h(x) = 4x
To find: f(x)-h(x)
f(x)-h(x)= 17x + 9 - 4x
= 13x + 9
Therefore, f(x)-h(x) = 13x + 9.
<u>Hope it helps!</u>
-6k+7k equals 1k.................................
The answer is D.
The full specification of Newton's First Law is (from Wikipedia)
In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force.
On earth we're generally in slightly a non-inertial frame, with rotation and revolution around the sun. It's also impossible to turn of gravity, so objects are being acted upon by an outside force. Typically there's also the outside force of friction, which makes things tend to stop.
