Answer:
0.0375 ohms
Explanation:
The resistance of a material is the product of the resistivity of the material by the length of the material divided by its cross-section area.
Mathematically,
resistance= resistivity × length/area
In this case the resistivity of the material is the same, and the length is the same thus, assume a length of 1 unit, the cross-section area is the one changing
In applying the formula,
resistivity is r and length is l=1 unit, find the resistivity the material as;
resistance= resistivity * length /area
0.075=r*1/1.04
0.075=r*0.9615
0.075/0.9615 =r
r=0.078
use the r=0.078 , a length of 1 unit (assumed), and area of 2.08 mm² to find the new resistance
Resistance= resistivity * length /area
Resistance = 0.078*1/2.08
Resistance= 0.078 * 0.4807 = 0.0375 ohms
Point to note here is that the greater the cross-section area, the less the resistance.
Answer:
For This Answer Please See the Attached File.
Explanation:
Answer:
ω=314.15 rad/s.
0.02 s.
Explanation:
Given that
Motor speed ,N= 3000 revolutions per minute
N= 3000 RPM
The speed of the motor in rad/s given as
Now by putting the values in the above equation
ω=314.15 rad/s
Therefore the speed in rad/s will be 314.15 rad/s.
The speed in rev/sec given as
ω= 50 rev/s
It take 1 sec to cover 50 revolutions
That is why to cover 1 revolution it take
Answer:
(a) Precipitation hardening - 1, 2, 4
(b) Dispersion strengthening - 1, 3, 5
Explanation:
The correct options for each are shown as follows:
Precipitation hardening
From the first statement; Dislocation movement is limited by precipitated particles. This resulted in an expansion in hardness and rigidity. Precipitates particles are separated out from the framework after heat treatment.
The aging process occurs in the second statement; because it speaks volumes on how heated solutions are treated with alloys above raised elevated temperature. As such when aging increases, there exists a decrease in the hardness of the alloy.
Also, for the third option for precipitation hardening; This cycle includes the application of heat the alloy (amalgam) to a raised temperature, maintaining such temperature for an extended period of time. This temperature relies upon alloying components. e.g. Heating of steel underneath eutectic temperature. Subsequent to heating, the alloy is extinguished and immersed in water.
Dispersion strengthening
Here: The effect of hearting is not significant to the hardness of alloys hardening by the method in statement 3.
In statement 5: The process only involves the dispersion of particles and not the application of heat.
Idk honestly just tryna get points.
