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zhuklara [117]
3 years ago
5

Which of the following is not a primary or fundamental dimension? (a)-mass m (b)-length L (c)- timer t (d)-volume V

Engineering
1 answer:
jolli1 [7]3 years ago
8 0

Answer:

Volume is not the fundamental dimension. So, option d is correct.

Explanation:

Step1

Fundamental dimension is the dimension in which other quantities depend. These are the basic dimensions. Three basic fundaments dimensions are mass, length and time that is represented as MLT respectively.

Step2

Volume is not the fundamental dimension among them as the volume is cube of length dimension. Thus, volume depends upon length.

Thus, Volume is not the fundamental dimension. So, option d is correct.

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An industrial system is rated at 600 v the system includes a partially exposed terminal block thats mounted on a bulkhead a new
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10 ft or 3.048 m (for unqualified person)

1.09 ft or 0.33 m (for qualified person)

Explanation:

OSHA has prescribed "Minimum Approach Distance - MAD" to ensure safety of personnel working with electrical power lines.

For a unqualified person:

The minimum approach distance is 10 ft or 3.048 m

For a qualified person:

For a voltage in the range of 300V to 750V (Phase to Ground or Phase to Phase) the minimum approach distance is 1.09 ft or 0.33 m

Since 600V lies in the above range hence it is applicable on 600V.

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2 years ago
Silicone elastomers, for use in seals and gaskets, are not compatible with which refrigerants?
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Silicone elastomers, for use in seals and gaskets, are not compatible with which refrigerants? answer is HFO'S

Explanation:

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2 years ago
What is the ratio between the viscosities of air and water at 10°C? What is the ratio between their kinematic viscosities at thi
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3 years ago
A pair of spur gears with 20 degree pressure angle, full-depth, involute teeth transmits 65 hp. The pinion is mounted on a shaft
vfiekz [6]

Answer:

See explaination

Explanation:

a) The pitch circle diameter of pinion in inches is given by

Dp=Np/P

Where

Np= No. of teeth in pinion = 26

P =diametral pitch= 6

Hence

Dp= 26/6 = 4.333 in

Pinion angular speed\omega _{p} =1250 rpm = 130.9 rad/s

Therefore pitch line speed

V=Dp/2\omega _{p} = 4.333/2x130.9

= 283.62 in/s

V= 23.63 ft/s

V=1418 ft/min

b) The pitch circle diameter og gear is given by

Dg= Ng/P= 48/6 = 8 in

The center distance is given by

C=(Dp+Dg)/2

= (4.333+8)/2

C= 6.167 in

c) The torque on the pinion is given by

Tp= P/\omega _{p}

Where

P = transmitted power, =65 hp = 65x550= 35750 lt-lb/s

Tp= 35750/130.9

= 273.1 ft-lb

d) Speed ratio is given as

R=Ng/Np= 48/26 = 1.8461

Hence speed of gear is

\omega _{g}=\frac{\omega _{p}}{R}

= 130.9/1.8461

= 70.9 rad/s

Therefore torque on gear is given as

Tg= P/\omega _{g} = 35750/70.9

= 504.2 ft-lb

e) Assuming transmission eficiency of 100%

Output hp=input hp= 65 hp

f) Tangential force on gear teeth is given by

Fgt= Tg/(Dg/2)

= 504.2x2/8

= 126.05 lb

g) Radial force on ger teeth is given as

Fgr= Fgt tan\phi

Where

\phi is pressure angle = 200

Hence

Fgr= 126.05tan200

= 45.88 lb

h) The normal force on gear teeth is given as

F=Fgt/cos\phi

= 126.05/cos200

= 134.14 lb

4 0
3 years ago
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