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polet [3.4K]
3 years ago
10

THIS SIGN MEANS: A. The right lane will end ahead B. The highway will be divided ahead C. Less space between lanes ahead

Engineering
1 answer:
hodyreva [135]3 years ago
7 0
B.) the highway will be divided ahead
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To reduce the negative impacts of stress on your mental
soldi70 [24.7K]

Answer:

A&C

Explanation:

breathing deeply is relaxing

talking with a friend can helping

4 0
2 years ago
Read 2 more answers
A student takes 60 voltages readings across a resistor and finds a mean voltage of 2.501V with a sample standard deviation of 0.
Lena [83]

Answer:

There are 2 expected readings greater than 2.70 V

Solution:

As per the question:

Total no. of readings, n = 60 V

Mean of the voltage, \mu = 2.501 V

standard deviation, \sigma = 0.113 V

Now, to find the no. of readings greater than 2.70 V, we find:

The probability of the readings less than 2.70 V, P(X\leq 2.70):

z = \frac{x - \mu}{\sigma} = \frac{2.70 - 2.501}{0.113} = 1.761

Now, from the Probability table of standard normal distribution:

P(z\leq 1.761) = 0.9608

Now,

P(X\geq 2.70) = 1 - P(X\leq 2.70) = 1 - 0.9608 = 0.0392 = 3.92%

Now, for the expected no. of readings greater than 2.70 V:

P(X\geq 2.70) = \frac{No.\ of\ readings\ expected\ to\ be\ greater\ than\ 2.70\ V}{Total\ no.\ of\ readings}

No. of readings expected to be greater than 2.70 V = P(X\geq 2.70)\times Total\ no.\ of\ readings

No. of readings expected to be greater than 2.70 V = 0.0392\times 60 = 2.352 ≈ 2

7 0
3 years ago
4. Which 2D shape on the left would be used to make the 3D shape on the right? (1 pt.)
dexar [7]

it would be a bc its a sqare?well 3d is like you can say a cube 2d is like flat

Explanation:

7 0
2 years ago
: During a heavy rainstorm, water from a parking lot completely fills an 18-in.- diameter, smooth, concrete storm sewer. If the
Montano1993 [528]

Answer

diameter of parking lot = 18 in

flowrate = 10 ft³/s

pressure drop = 100 ft

using general equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g}+Z_1 = \dfrac{P_2{\gamma} + \dfrac{v_2^2}{2g} + Z_2 +\dfrac{fLV^2}{2\rho D}

V = \dfrac{Q}{A} = \dfrac{10}{\dfrac{\pi}{4}(\dfrac{18}{12})^2} = 5.66\ ft/s

\Delta P = \gamma (Z_2-Z_1) +\dfrac{fLV^2}{2\rho D}

taking f = 0.0185

at Z₁ = Z₂

\Delta P = \dfrac{0.0185 \times 100\times 1.94\times 5.66^2}{2\dfrac{18}{12} (2)}

ΔP = 0.266 psi

b) when flow is uphill z₂-z₁ = 2

\Delta P =62.4\times 2 \times \dfrac{1}{144} +0.266

\Delta P= 1.13\ psi

c) When flow is downhill  z₂-z₁ = -2

\Delta P =62.4\times 2 \times \dfrac{1}{144} +0.266

\Delta P=-0.601\ psi

7 0
3 years ago
does anyone have the answers to the modern carpentry book review questions for chapter 21,22, and 23​
larisa [96]
You could go on Slader and look for the book, it gives you answer keys
4 0
2 years ago
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