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svet-max [94.6K]
3 years ago
9

We know that passengers can be either helpful or harmful to a driver. Describe a pro and a con of having passengers in your car.

Also, explain a strategy you will use to manage teen passengers that ensures safety in your vehicle.
Engineering
2 answers:
AveGali [126]3 years ago
8 0

Question: <em>We know that passengers can be either helpful or harmful to a driver. Describe a pro and a con of having passengers in your car. Also, explain a strategy you will use to manage teen passengers that ensures safety in your vehicle.</em>

Answer: Pros:

- Pro: Most public transportation fares are cheaper than driving your car across town. There are usually discounted fares for students, disabled, seniors, and children(it may be even free to ride with a student I.D, for college students. Some buses may offer discount monthly passes as well.

- Pro: You can save gas and money, especially if your commute is long. Even if you don't get a discounted fare, the amount of money saved by not driving around could be substantial.

- Pro: There's no need to worry about being stuck in traffic, or finding a parking spot in a crowded parking lot.Whether you are headed to work or school, the added time of finding a parking spot can be the difference between being late and making it on time.  

Most buses stop near or in front of major destinations, from shopping centers to universities. This allows you to get off on or near campus without the added worry of finding parking.

- Pro: For students, the added benefit of not having to pay for a semester parking pass. The cost of semester parking permits can be the upwards of $100, so taking public transportation can eliminate that cost, and allow you to save or spend that $100 elsewhere (maybe on groceries?).

Cons:

- Con: Buses can delay, so plan on getting an hour early to your destination in preparation for delays. There are a number of reasons why a bus can be delayed, from a driver calling out sick or the bus having engine problems.    

- Con: Keeping track of the buses/trains, and the stop times can be hectic, especially in larger cities. Most timetables and transit maps are available for any major city online, but the amount of lines and routes intersecting can be overwhelming.  

Some sites offer a trip planner, where you can enter your destinations and the best route can be calculated for you. If not, there is usually time tables provided at the transit stations or on the buses themselves that you have to look at and pick out which route works best.  

- Con: Some bus stops, or areas can be unsafe, so always be aware of surroundings. Make sure your stop is well-lit at night, and always be aware of who is sitting/standing with you at a specific stop or station.  

If you don't feel comfortable waiting for a while at a particular stop, try to find an alternate stop nearby that is occupied by more people and maybe a bit safer than the original stop.

anygoal [31]3 years ago
6 0

Answer:

sub to pewdipie

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What are the controlling LRFD load combinations for dead and floor live load?
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Answer:

1) 1.4(D + F)

2) 1.2(D + F + T) + 1.6(L + H) + 0.5(Lr or S or R)

3) 1.2D + 1.6(Lr or S or R) + ((0.5 or 1.0)*L or 0.8W)

4) 1.2D + 1.6W + (0.5 or 1.0)*L + 0.5(Lr or S or R)

5) 1.2D + 1.0E + (0.5 or 1.0)*L + 0.2S

6) 0.9D + 1.6W + 1.6H

7) 0.9D + 1.0E + 1.6H

Explanation:

Load and Resistance Factor Design

there are 7 basic load combination of LRFD that is

1) 1.4(D + F)

2) 1.2(D + F + T) + 1.6(L + H) + 0.5(Lr or S or R)

3) 1.2D + 1.6(Lr or S or R) + ((0.5 or 1.0)*L or 0.8W)

4) 1.2D + 1.6W + (0.5 or 1.0)*L + 0.5(Lr or S or R)

5) 1.2D + 1.0E + (0.5 or 1.0)*L + 0.2S

6) 0.9D + 1.6W + 1.6H

7) 0.9D + 1.0E + 1.6H

and

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here

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Read 2 more answers
Calculate the reluctance of a 4-meter long toroidal coil made of low-carbon steel with an inner radius of 1.75 cm and an outer r
My name is Ann [436]

Answer:

R = 31.9 x 10^(6) At/Wb

So option A is correct

Explanation:

Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A

Thus; R = L/μA,

Now from the question,

L = 4m

r_1 = 1.75cm = 0.0175m

r_2 = 2.2cm = 0.022m

So Area will be A_2 - A_1

Thus = π(r_2)² - π(r_1)²

A = π(0.0225)² - π(0.0175)²

A = π[0.0002]

A = 6.28 x 10^(-4) m²

We are given that;

L = 4m

μ_steel = 2 x 10^(-4) Wb/At - m

Thus, reluctance is calculated as;

R = 4/(2 x 10^(-4) x 6.28x 10^(-4))

R = 0.319 x 10^(8) At/Wb

R = 31.9 x 10^(6) At/Wb

8 0
3 years ago
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