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svet-max [94.6K]
3 years ago
9

We know that passengers can be either helpful or harmful to a driver. Describe a pro and a con of having passengers in your car.

Also, explain a strategy you will use to manage teen passengers that ensures safety in your vehicle.
Engineering
2 answers:
AveGali [126]3 years ago
8 0

Question: <em>We know that passengers can be either helpful or harmful to a driver. Describe a pro and a con of having passengers in your car. Also, explain a strategy you will use to manage teen passengers that ensures safety in your vehicle.</em>

Answer: Pros:

- Pro: Most public transportation fares are cheaper than driving your car across town. There are usually discounted fares for students, disabled, seniors, and children(it may be even free to ride with a student I.D, for college students. Some buses may offer discount monthly passes as well.

- Pro: You can save gas and money, especially if your commute is long. Even if you don't get a discounted fare, the amount of money saved by not driving around could be substantial.

- Pro: There's no need to worry about being stuck in traffic, or finding a parking spot in a crowded parking lot.Whether you are headed to work or school, the added time of finding a parking spot can be the difference between being late and making it on time.  

Most buses stop near or in front of major destinations, from shopping centers to universities. This allows you to get off on or near campus without the added worry of finding parking.

- Pro: For students, the added benefit of not having to pay for a semester parking pass. The cost of semester parking permits can be the upwards of $100, so taking public transportation can eliminate that cost, and allow you to save or spend that $100 elsewhere (maybe on groceries?).

Cons:

- Con: Buses can delay, so plan on getting an hour early to your destination in preparation for delays. There are a number of reasons why a bus can be delayed, from a driver calling out sick or the bus having engine problems.    

- Con: Keeping track of the buses/trains, and the stop times can be hectic, especially in larger cities. Most timetables and transit maps are available for any major city online, but the amount of lines and routes intersecting can be overwhelming.  

Some sites offer a trip planner, where you can enter your destinations and the best route can be calculated for you. If not, there is usually time tables provided at the transit stations or on the buses themselves that you have to look at and pick out which route works best.  

- Con: Some bus stops, or areas can be unsafe, so always be aware of surroundings. Make sure your stop is well-lit at night, and always be aware of who is sitting/standing with you at a specific stop or station.  

If you don't feel comfortable waiting for a while at a particular stop, try to find an alternate stop nearby that is occupied by more people and maybe a bit safer than the original stop.

anygoal [31]3 years ago
6 0

Answer:

sub to pewdipie

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A parallel circuit with two branches and an 18 volt battery. Resistor #1 on the first branch has a value of 220 ohms and resisto
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Explanation:

The power dissipated in each branch is ...

  P = V^2/R

So, the branch powers are ...

  branch 1: 18^2/220 ≈ 1.473 W

  branch 2: 18^2/330 ≈ 0.982 W

Total power is ...

  1.473 W + 0.982 W = 2.455 W

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Exercise 19
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1 kg of saturated steam at 1000 kPa is in a piston-cylinder and the massless cylinder is held in place by pins. The pins are rem
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Answer:

The final specific internal energy of the system is 1509.91 kJ/kg

Explanation:

The parameters given are;

Mass of steam = 1 kg

Initial pressure of saturated steam p₁ = 1000 kPa

Initial volume of steam, = V₁

Final volume of steam = 5 × V₁

Where condition of steam = saturated at 1000 kPa

Initial temperature, T₁  = 179.866 °C = 453.016 K

External pressure = Atmospheric = 60 kPa

Thermodynamic process = Adiabatic expansion

The specific heat ratio for steam = 1.33

Therefore, we have;

\dfrac{p_1}{p_2} = \left (\dfrac{V_2}{V_1} \right )^k = \left [\dfrac{T_1}{T_2}   \right ]^{\dfrac{k}{k-1}}

Adding the effect of the atmospheric pressure, we have;

p = 1000 + 60 = 1060

We therefore have;

\dfrac{1060}{p_2} = \left (\dfrac{5\cdot V_1}{V_1} \right )^{1.33}

P_2= \dfrac{1060}{5^{1.33}}  = 124.65 \ kPa

\left [\dfrac{V_2}{V_1} \right ]^k = \left [\dfrac{T_1}{T_2}   \right ]^{\dfrac{k}{k-1}}

\left [\dfrac{V_2}{V_1} \right ]^{k-1} = \left \dfrac{T_1}{T_2}   \right

5^{0.33} = \left \dfrac{T_1}{T_2}   \right

T₁/T₂ = 1.70083

T₁ = 1.70083·T₂

T₂ - T₁ = T₂ - 1.70083·T₂

Whereby the temperature of saturation T₁ = 179.866 °C = 453.016 K, we have;

T₂ = 453.016/1.70083 = 266.35 K

ΔU = 3×c_v×(T₂ - T₁)

c_v = cv for steam at 453.016 K = 1.926 + (453.016 -450)/(500-450)*(1.954-1.926) = 1.93 kJ/(kg·K)

cv for steam at 266.35 K = 1.86  kJ/(kg·K)

We use cv given by  (1.93 + 1.86)/2 = 1.895 kJ/(kg·K)

ΔU = 3×c_v×(T₂ - T₁) = 3*1.895 *(266.35 -453.016) = -1061.2 kJ/kg

The internal energy for steam = U_g = h_g -pV_g

h_g = 2777.12 kJ/kg

V_g = 0.194349 m³/kg

p = 1000 kPa

U_{g1} = 2777.12 - 0.194349 * 1060 = 2571.11 kJ/kg

The final specific internal energy of the system is therefore, U_{g1} + ΔU = 2571.11 - 1061.2 = 1509.91 kJ/kg.

3 0
3 years ago
I WILL GIVE BRAINLIEST IF ANSWER FAST What is the measurement of this dial caliper?
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6 0
4 years ago
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Using the data in the photo write the complex waveform expression​
UNO [17]

Answer:

1st Harmonic:

v(t) = 50\cos(2000\pi t)

3rd Harmonic:

v(t) = 9\cos(6000\pi t)

5th Harmonic:

v(t) = 6\cos(10000\pi t)

7th Harmonic:

v(t) = 2\cos(14000\pi t)

Explanation:

The general form to represent a complex sinusoidal waveform is given by

v(t) = A\cos(2\pi f t + \phi)

Where A is the amplitude in volts of the sinusoidal waveform

Where f is the frequency in cycles per second (Hz) of the sinusoidal waveform

Where \phi is the phase angle in radians of the sinusoidal waveform.

1st Harmonic:

We have A = 50, f = 1000 and φ = 0

v(t) = 50\cos(2\pi 1000 t + 0) \\\\v(t) = 50\cos(2000\pi t)

3rd Harmonic:

We have A = 9, f = 3000 and φ = 0

v(t) = 9\cos(2\pi 3000 t + 0) \\\\v(t) = 9\cos(6000\pi t)

5th Harmonic:

We have A = 6, f = 5000 and φ = 0

v(t) = 6\cos(2\pi 5000 t + 0) \\\\v(t) = 6\cos(10000\pi t)

7th Harmonic:

We have A = 2, f = 7000 and φ = 0

v(t) = 2\cos(2\pi 7000 t + 0) \\\\v(t) = 2\cos(14000\pi t)

Note: The even-numbered harmonics have 0 amplitude that is why they are not shown here.

8 0
4 years ago
Read 2 more answers
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