Answer:
maximum allowable electrical power=4.51W/m
critical radius of the insulation=13mm
Explanation:
Hello!
To solve this heat transfer problem we must initially draw the wire and interpret the whole problem (see attached image)
Subsequently, consider the heat transfer equation from the internal part of the tube to the external air, taking into account the resistance by convection, and conduction as shown in the attached image
to find the critical insulation radius we must divide the conductivity of the material by the external convective coefficient
Step 1:
Start by setting it up with the divisor 8 on the left side and the dividend 27 on the right side like this:
8 ⟌ 2 7
Step 2:
The divisor (8) goes into the first digit of the dividend (2), 0 time(s). Therefore, put 0 on top:
0
8 ⟌ 2 7
Step 3:
Multiply the divisor by the result in the previous step (8 x 0 = 0) and write that answer below the dividend.
0
8 ⟌ 2 7
0
Step 4:
Subtract the result in the previous step from the first digit of the dividend (2 - 0 = 2) and write the answer below.
0
8 ⟌ 2 7
- 0
2
Step 5:
Move down the 2nd digit of the dividend (7) like this:
0
8 ⟌ 2 7
- 0
2 7
Step 6:
The divisor (8) goes into the bottom number (27), 3 time(s). Therefore, put 3 on top:
0 3
8 ⟌ 2 7
- 0
2 7
Step 7:
Multiply the divisor by the result in the previous step (8 x 3 = 24) and write that answer at the bottom:
0 3
8 ⟌ 2 7
- 0
2 7
2 4
Step 8:
Subtract the result in the previous step from the number written above it. (27 - 24 = 3) and write the answer at the bottom.
0 3
8 ⟌ 2 7
- 0
2 7
- 2 4
3
You are done, because there are no more digits to move down from the dividend.
The answer is the top number and the remainder is the bottom number.
Therefore, the answer to 27 divided by 8 calculated using Long Division is:
3
Two forces P and Q whose resultant is 10Newton are at right angles to each other. If P makes 30 degrees with resultant.Show me the workings of the magnitude of Q in Newton and the diagram of the vectors.
Answer:
something that involves cars
Explanation:
Answer:
Total wight =640.7927 KN
Explanation:
Given that
do= 61 cm
L =120
t= 0.9 cm
That is why inner diameter of the pipe
di= 61 - 2 x 0.9 cm
di=59.2 cm
Water density ,ρ = 1 kg/L = 1000 kg/m³
Weight of the pipe ,wt = 2500 N/m
wt = 2500 x 120 N = 300,000 N
The wight of the water
wt ' = ρ V g
wt'=340792.47 N
That is why total wight
Total wight = wt + wt'
Total wight =300,000+ 340792.47 N
Total wight =640,792.47 N
Total wight =640.7927 KN
