All categories

3 years ago

Please help and show the steps please

Mathematics

1 answer:

Lynna [10]3 years ago

6 0

First we solve for y₁
3×5 - 5y₁ = 20
15 - 5y₁ = 20
-5y₁ = 20 - 15
-5y₁ = 5
y₁ = -1
(5, -1)

Now we solve for x₂
3x₂ - 5×2 = 20
3x₂ - 10 = 20
3x₂ = 20 + 10
3x₂ = 30
x₂ = 10
(10, 2)

You might be interested in

Write as a fraction in the simplest from 80%

Georgia [21]

Answer:

4/5

Step-by-step explanation:

5 0

3 years ago

I Will give out brainliest help ASAP

kirza4 [7]

Step-by-step explanation:

f(x) = 2x² + 9

f(5) = 2(5)² + 9

= 2(25) + 9

= 50 + 9

= 59

6 0

3 years ago

A net of a building block is shown below. What is the total surface area of the building block? *

777dan777 [17]

Answer:

where

Step-by-step explanation:

6 0

2 years ago

Bill has these expenditures for his utilities: December,

Brrunno [24]

The average monthly expenses for Bill's utilities is $266.67.

It is given in the question that:-

Expenditure in December by Bill = $ 234.45

Expenditure in January by Bill = $ 281.23

Expenditure in February by Bill = $ 284.33

We have to find the average monthly expenses for Bill's utilities.

We know that,

Average monthly expense for utilities = (Expenditure in December + Expenditure in January + Expenditure in February)/3

Hence, using the data given in the question, we can write,

Average monthly expense for utilities = (234.45 + 281.23 + 284.33)/3

Average monthly expense for utilities = 800.01/3 = $266.67

To learn more about average, here:-

brainly.com/question/24057012

#SPJ1

6 0

1 year ago

The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 38 feet and

forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}$

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

$a=\frac{38}{2}=19ft$

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

$\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}$

and we can simplify the equation, so we get:

$\frac{x^2}{361}+\frac{y^2}{144}$

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

$\frac{y^{2}}{144}=1-\frac{x^{2}}{361}$

$y^{2}=144(1-\frac{x^{2}}{361})$

we can add everything inside parenthesis so we get:

$y^{2}=144(\frac{361-x^{2}}{361})$

and take the square root on both sides, so we get:

$y=\sqrt{144(\frac{361-x^{2}}{361})}$

and we can simplify this so we get:

$y=\frac{12}{19}\sqrt{361-x^{2}}$

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

$y=\frac{12}{19}\sqrt{361-(8)^{2}}$

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0

3 years ago