It would be 2(x+3)(x+1)=0
Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
Answer:
A. (0,7)
B. -1.25
C. Negative
D. I started at (0,7), then plotted the second point by moving the point down 5 and right 4.
Step-by-step explanation:
Look at the equation more carefully.
I hope this helps :)
Answer:
51 were the total number of the tickets sold at a school carnival were early-admission tickets.
Step-by-step explanation:
Total number of tickets sold by = 100
Let 
be the early-admission tickets sold by the school.
As 51% of the tickets sold at a school carnival were early-admission tickets.
so
Therefore, 51 were the total number of the tickets sold at a school carnival were early-admission tickets.
Answer:
4^y = x + 3
2^y = x + 2
Step-by-step explanation:
log_4(x + 3 ) = log_2 (2 + x )
log_4( x + 3 ) = y
log_2 (2 + x ) = y
4^y = x + 3
2^y = x + 2
