Answer: 5n = 3d and 3n + 6 = 2d + 4
Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.
We are to select the system of equations that could be used to solve the problem.
Since n denotes the numerator and m denotes the denominator of the given fraction, so we have:
n/d = 3/5
5n = 3d
<h3>and</h3>
(n+2)/(d+2) = 2/3
3(n+2) = 2(d+2)
3n + 6 = 2d + 4
Thus, the required system of equations is,
5n = 3d and 3n + 6 = 2d + 4
Brainliest pweaseee if the answer is clear and correct! <3 ~~~
The answer is D. -2x+5.
If we simplify the left side of the equation first given, we come to the expression -2x-10.
If we solve for D., we get the same results. Thus, because an equation with all the same variable terms and constants have infinite solutions, the answer is D.
Hope this helps!
