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Fantom [35]
3 years ago
10

A NASA mathematician used a system of equations to determine the point in space where a satellite crossed paths with a massive p

iece of space debris. How many equations did he need? And how many variables were needed to find the exact location in space?
A) 3 equations with 2 variables

B) 2 equations with 2 variables

C) 2 equations with 3 variables

D) 3 equations with 3 variables
Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0

Answer:

Option D.

3 equations with 3 variables

Step-by-step explanation:

The coordinates of a point in space must necessarily have 3 components. One to describe the distance on the x axis, another to describe the distance on the y axis to the point, and a third to describe the distance on the z axis.

If we have three variables, then 3 equations are needed to solve the system. With less than 3 equations it would be impossible to solver the system.

Therefore the correct answer is option D.

3 equations with 3 variables

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The graph of which function has an amplitude of 3 and a right phase shift of ?
cricket20 [7]

Answer:

The first one

Step-by-step explanation:

The amplitude is usually the first number (for example, in this equation, the 3). Then you also know that the right or left shift depends on the addition or subtraction sign. Usually, the subtraction sign means to the right and the addition sign means to the left.

8 0
2 years ago
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Genrish500 [490]
B 16 miles an hour

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3 0
2 years ago
25. If mVYX = 276° and m angle UVX = (4x - 5),
katovenus [111]

Answer:

22.25 or 22

Step-by-step explanation:

360-276+=84

4x-5=84

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6 0
2 years ago
V= pi r^2h solve for h
Ivenika [448]

Divide each term by πr2 π r 2 and simplify. Divide each term in πr2h=V π r 2 h = V by πr2 π r 2 .

7 0
3 years ago
Which expression is equivalent to (p^10r^−5)^1/5 ?
meriva

Answer:

p^2/r

Step-by-step explanation:

An equivalent expression is the expression in simplest form. Here apply exponent rules by multiplying the exponents of each term by 1/5.

(p^{10}r^{-5})^{\frac{1}{5}}\\\\(p^{\frac{10}{5}}r^{\frac{-5}{5}})\\\\p^2r^{-1}\\\\\frac{p^2}{r}

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3 years ago
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