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3 years ago

13

Find the equation of the tangent line to the curve y=x sqrtx at point (4,8) Y=?

1 answer:

Viefleur [7K]3 years ago

7 0

Answer: I think y is 32 im not good at this tho

Step-by-step explanation:

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Will give medal !!!!

Sholpan [36]

We can use the formula: y = mx + b.

Where m = 2/3 (slope) and (x,y) is (1,1)

Now substitute the values in order to find what "b" is.

1 = (2/3)*1 + b

1 = 2/3 + b

1 - 2/3 = b

1/3 = b

So the equation of the line is: y = (2/3)x + 1/3

To get it into standard form, it should be in the form Ax + By = C

So just multiply the equation by 3 to get rid of the fraction:

3y = 2x + 1

-2x + 3y = 1

Final answer: -2x + 3y = 1

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Alex787 [66]

Answer:

$D. \: y = \frac{1}{3} x - 4$

Step-by-step explanation:

The y-intercept of the graph is <u>(0,-4)</u>. The slope goes <u>one</u><u> </u><u>unit</u><u> </u><u>up</u><u> </u><u>and</u><u> </u><u>three</u><u> </u><u>units</u><u> </u><u>right</u>.

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