3a to the power of 2 plus 5a minus 2
Let's see here... well, since the first letter in the ratio is from the first triangle, then, the first one in the equal ratio is going to have to be that as well, and the ratio of c:a wouldn't work, since c was already used. By process of elimination, it's gotta be b:q.
F(x) = x² + 4
y = x² + 4
First, I reverse the equation to be
x² + 4 = y
Second, we need only x to remain on the left side and we need to move the others to the right side
x² + 4 = y
x² = y - 4
x = √(y - 4)
Last, change into invers function
f⁻¹(x) = √(x - 4)
