6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks
<u>Step-by-step explanation:</u>
We have , Trenton and Maria record how much dry food their pets eat on average each day.• Trenton's pet: 4/5 cup of dry food• Maria's pet: 1.25 cups of dry food. Based on these averages . We need to find how many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks . We need to find how much they eat for 14 days as:
Trenton's pet: 4/5 cup of dry food•
With 4/5 per day , for 14 days :
⇒
⇒
⇒
Maria's pet: 1.25 cups of dry food.
With 1.25 per day , for 14 days :
⇒
⇒
Subtracting Maria's - Trenton's :
⇒
That means , 6.3 many more cups of dry food will Maria's pet have eaten than Trenton's pet will have eaten over 2 seven-day weeks
Answer: 29.2
Step-by-step explanation:
The lengths of the two longer legs are both
The lengths of the two shorter legs are both
So
C=2 times j
c=2j
o=j-6
c+j+o=58
subsitte j-6 for o and 2j for c
2j+j+j-6=58
4j-6=58
add 6 to both sides
4j=64
divide both sides by 4
j=16
sub back
c=2j
c=2(16)
c=32
o=j-6
o=16-6
o=10
curtis=32
olivia=10
jonathan=16
equations are
c+j+o=58
c=2j
o=j-6
Answer:
f^(−1)(x)= x/6+4
Step-by-step explanation:
interchange the variables and solve for
y