Hello There!
Area = l x w
14 =
Multiples of 14:
1 and 14
7 and 2
7 and 2 are the only ones with a difference of 5.
Therefore, the length is 7ft and the width is 2ft.
Hope This Helps You!Good Luck :)
- Hannah ❤
Answer:
Step-by-step explanation:
Find the midpoint of each frequency range, multiply that number by the frequency, sum up and divide by the total frequency.
This will give the mean number.
<u>The mean is:</u>
- [17*( 3 + 3.5)/2 + 21*(3.5 + k)/2 + 33*(k + 4)/2 + 54*(4 + 4.5)/2 + 15*(4.5 + 6)/2]/140 = 4.09
- 55.25 + 10.5k + 36.75 + 16.5k + 66 + 229.5 + 78.75 = 140*4.09
- 17k + 466.25 = 572.6
- 17k = 572.6 - 466.25
- 17k = 106.35
- k = 106.35/17
- k = 6.26
Note, I expected the value of k between 3.5 and 4. This is a bit of illogical outcome.
Answer:
Step-by-step explanation:
Mr Thompson wants to protect his garage by installing a flood barrier. He connects 2 barriers side by side. The length of each flood barrier is 9 ft while the height of each barrier is 2 ft. The barriers are rectangular in shape. The area of each rectangular barrier is expressed as length × height.
Therefore
Area of each barrier is 9 × 2 = 18 ft^2
The combined area of the barriers would be
18 × 2 = 36 ft^2
5th term = a1r^4 where a1 = first term and r = common ratio
so 1/4 = a1 * (1/2)^4
a1 = 1/4 / (1/2)^4 = 4
so the sequence is 4 , 4*1/2, 4*(1/2)^2...
= 4, 2, 1, 1/2, 1/4 .....
Answer:
Number of questions constraint:
x + y ≥ 15
Time constraint :
5x + 8y ≤ 120
Step-by-step explanation:
Let :
x = number of equations
y = number of word problems
Number of answers required = atleast 15
Equation takes 5 minutes
Word problem takes 8 minutes
Time available to complete exam = 120 minutes
Constraints :
Number of questions required
Total questions shout be atleast 15
x + y ≥ 15
Time constraint :
5x + 8y ≤ 120
