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Juli2301 [7.4K]
3 years ago
8

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

.)
h(t) = t3/4 − 3t1/4
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
H(t) = t^(3/4) - 3t^(1/4)

The critical points can be evaluated by taking the first derivative and equating to 0.

h'(t) = 3 / t^(1/4)  - 3 / 4t^(3/4)
3 / (4t^(3/4)) = 3 / t^(1/4)
4t^(3/4) = t^(1/4)

4 = 1/√t
t = 1/16, t = -1/16
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Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negat
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Answer:

Answer:

(5, 20)  

Step-by-step explanation:

We can find the slope of the line

m = (y2-y1)/(x2-x1)

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Since the line goes through (0,0) the y intercept is 0

y = mx+b

y = 4x

Lets check the points  by substituting into the equation

40, 10)     10 = 4*40   10 =160  no

(–5, –10)    -10 = 4*-5    10 = -20   no

(5, 20)       20 = 4*5    20 = 20  yes

(–10, –20)    -20 = 4*-10    -20 = -40   no

Step-by-step explanation:

Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negative slope goes through points (negative 20, 10), (0, 0), and (20, negative 10). (10, –20) (–30, 20) (–10, 5) (35, –20)

4 0
3 years ago
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Answer:

The correct option is 4.

Step-by-step explanation:

The given function is

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Where f(x) is height of the ball and x is the distance.

It is a polynomial function with degree 2. All polynomial functions are defined for all real numbers, therefore the mathematical domain of the function is all real numbers.

-\infty

Factorize the given function.

f(x)=-0.05(x^2-50x-104)

f(x)=-0.05(x^2-50x-104)

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Put f(x)=0 to find the x intercepts.

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Equate each factor equal to 0.

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Therefore at x=52 and -2, the graph of f(x) intersects x-axis. Before x=-2 and after x=52 the values of f(x) is negative. Height cannot be negative, therefore reasonable domain is lie between -2 to 52.

Distance cannot be negative, therefore the reasonable domain must be positive.

0\leq x\leq 52

Therefore the reasonable domain is 0\leq x\leq 52 and option 4 is correct.

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