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Juli2301 [7.4K]
3 years ago
8

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

.)
h(t) = t3/4 − 3t1/4
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
H(t) = t^(3/4) - 3t^(1/4)

The critical points can be evaluated by taking the first derivative and equating to 0.

h'(t) = 3 / t^(1/4)  - 3 / 4t^(3/4)
3 / (4t^(3/4)) = 3 / t^(1/4)
4t^(3/4) = t^(1/4)

4 = 1/√t
t = 1/16, t = -1/16
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Step-by-step explanation:

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Answer:

\displaystyle m\angle AED=32.5^\circ

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

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\displaystyle m\angle AED=32.5^\circ

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Cube
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Read 2 more answers
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