Consider these two electron configurations for neutral atoms l and m. l - 1s22s22p63s2 m - 1s22s22p63s13p1 what is the atomic nu
2 answers:
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<u>Answer:</u> The total amount of leftover reactants and HCl is 12.79 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For hydrogen gas:</u>
Given mass of hydrogen gas = 0.36 g
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
- <u>For chlorine gas:</u>
Given mass of chlorine gas = 12.41 g
Molar mass of chlorine gas = 71 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of hydrogen gas and chlorine gas is:
By Stoichiometry of the reaction:
1 moles of chlorine gas reacts with 1 mole of hydrogen gas
So, 0.175 moles of chlorine gas will react with = of hydrogen gas
As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, chlorine gas is considered as a limiting reagent because it limits the formation of product.
Moles of excess reactant left (hydrogen gas) = [0.18 - 0.175] = 0.005 moles
By Stoichiometry of the reaction
1 moles of chlorine gas produces 2 moles of HCl
So, 0.175 moles of chlorine gas will produce = moles of HCl
Now, calculating the mass of hydrogen gas left and HCl from equation 1, we get:
- <u>For hydrogen gas:</u>
Molar mass of hydrogen gas = 2 g/mol
Moles of excess hydrogen gas = 0.005 moles
Putting values in equation 1, we get:
- <u>For HCl:</u>
Molar mass of HCl = 36.5 g/mol
Moles of HCl = 0.350 moles
Putting values in equation 1, we get:
Total mass of HCl and leftover reactants = [12.78 + 0.01] = 12.79 g
Hence, the total amount of leftover reactants and HCl is 12.79 grams
Given data:
Mass of cofactor A in an average yeast cell = 96.15 pg
Now:
1 picogram (pg) = 1* g
1 microgram (ug) = 1* g
Therefore, 1 pg = 1*ug
Mass of cofactor A in one yeast cell = 96.15 * micro gram
Number of cells in the yeast colony = 105
Therefore, the total mass of cofactor A is given as:
Number of cells * mass of cofactor A per cell
= 105 cells * 96.15 * micro grams/cell = 1.009 *
micro grams
Answer:
Mg₃(PO₄)₂
Explanation:
This is a neutralization reaction between an acid and a base
The acid here is H₃PO₄
base is Mg(OH)₂
Every chemical reaction is made up of reactants on the left side and products formed on the right hand side of the expression;
3Mg(OH)₂ + 2H₃PO₄
→ Mg₃(PO₄)₂
+ 6H₂O
The reaction above is a double replacement reaction in which two ionic compounds gives an insoluble precipitate as a product when their ions displace one another in solution.
The solid formed is Mg₃(PO₄)₂