1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
disa [49]
2 years ago
5

Al añadir 1g de urea a 100 ml de agua a 20ºC, la presión de vapor pasa de 17,54 mmHg a 17,49 mmHg. Determina la masa molecular d

e la urea.
Chemistry
1 answer:
never [62]2 years ago
3 0

Answer: Los  estudios  teóricos  y  experimentales  han  permitido  establecer,  que  los  líquidos  poseen  propiedades  físicas  características.  Entre  ellas  cabe  mencionar:  la  densidad,  la  propiedad  de  ebullir, congelar y evaporar, la viscosidad y la capacidad de conducir la corriente eléctrica, etc. Cada líquido presenta valores característicos (es decir, constantes) para cada una de estas propiedades.             Cuando            un            soluto  y  un  solvente  dan  origen  a  una  solución,  la  presencia  del  soluto  determina  una  modificación  de  estas  propiedades  con  relación  a  su  estado  normal  en  forma  aislada,  es  decir,  líquido  puro.  Estas  modificaciones  se  conocen  como  PROPIEDADES  DE  UNA SOLUCIÓN.

You might be interested in
Which isotope is appropriate for dating rocks that are billions of years old
Dominik [7]
I did the test and the answer is C.
4 0
3 years ago
Read 2 more answers
Nicotine, a component of tobacco, is composed of C, H, and N. A 7.875-mg sample of nicotine was combusted, producing 21.363 mg o
Gnom [1K]

Answer: The empirical formula for the given compound is C_5H_7N

Explanation:

The chemical equation for the combustion of compound having carbon, hydrogen, and nitrogen follows:

C_xH_yN_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of carbon, hydrogen and nitrogen respectively.

We are given:

Mass of CO_2=21.363mg=21.363\times 10^3g=21363g

Mass of H_2O=6.125g=6.125\times 10^3g=6125g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 21363 g of carbon dioxide, \frac{12}{44}\times 21363=5826.27g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 6125 g of water, \frac{2}{18}\times 6125=680.55 of hydrogen will be contained.

Now we have to calculate the mass of nitrogen.

Mass of nitrogen in the compound = (7875) - (5826.27 + 680.55) = 1368.18 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5826.27g}{12g/mole}=485.52moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{680.55g}{1g/mole}=680.55moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{1368.18g}{14g/mole}=97.73moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0154 moles.

For Carbon = \frac{485.52}{97.73}=4.96\approx 5

For Hydrogen  = \frac{680.55}{97.73}=6.96\approx 7

For Nitrogen = \frac{97.73}{97.73}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 5 : 7 : 1

Hence, the empirical formula for the given compound nicotine is C_5H_7N_1=C_5H_7N

7 0
3 years ago
How many atoms are in 2.45 moles of hydrogen
allochka39001 [22]

Answer:

There are 1.4754246675000002e+24 atoms of Hydrogen within the measurement of 2.45 moles of hydrogen!

Explanation:

6 0
3 years ago
an unknown sample required 21.05 mL of 0.02047 M KmnO4 to reach the end point. How many moles of KmnO4 reacted?
Angelina_Jolie [31]
.02047 = x / 0.02105 = 0.0004309mol
6 0
3 years ago
A rigid container is filled with chlorine gas. The gas has a pressure of 2.75 bar. The tank is then cooled down to -20.0oC at wh
Gnom [1K]

Answer:

Original temperature (T1) = - 37.16°C

Explanation:

Given:

Gas pressure (P1) = 2.75 bar

Temperature (T2) = - 20°C

Gas pressure (P2) = 1.48 bar

Find:

Original temperature (T1)

Computation:

Using Gay-Lussac's Law

⇒ P1 / T1 = P2 / T2

⇒ 2.75 / T1 = 1.48 / (-20)

⇒ T1 = (2.75)(-20) / 1.48

⇒ T1 = -55 / 1.48

⇒ T1 = - 37.16°C

Original temperature (T1) = - 37.16°C

3 0
3 years ago
Other questions:
  • How many moles of n are in 0.165 g of n2o?
    5·2 answers
  • What might happen if a patient was to have a hip replacement using aluminium?
    7·1 answer
  • What is nitrogen's melting point?
    15·1 answer
  • Similar fossils have been found in south america and ?
    10·1 answer
  • If an unknown liquid has a density of 0.756 g/mL and a mass of 2.00 g, what is its volume?
    14·1 answer
  • Suppose you want to test the results of a transformation by growing Escherichia coli cells in LB medium containing ampicillin as
    11·1 answer
  • What compound is missing?<br> 3Na2SO4 + 2AlCl3 →+ _____ + 6NaCl
    12·1 answer
  • WILL MARK BRAINLIEST! PLEASE HELP!!
    5·1 answer
  • Consider the reaction 3O2(g) 2O3(g) At 298 K, the equilibrium concentration of O2 is 1.6 x 10^-2 M, What is the equilibrium cons
    14·1 answer
  • What is the definition of a catalyst?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!