Find surface area of the prism

Solve the following problems. a. 2 ft. 5 in. + 9 in. b. 4 yd. 8 in + 6 yd. 6 in. c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. +

Arada [10]

a. 2 ft. 5 in. + 9 in.=2 ft 14 in.=2 ft. (12+2) in.=3 ft. 2 in. (since 1 ft.=12 in.);

 b. 4 yd. 8 in + 6 yd. 6 in. =(4+6) yd. (8+6) in.=10 yd. 14 in.=10 yd. (12+2) in.=10 yd. 1 ft. 2 in.;

c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. + 13 yd. 1 ft. 3 in.=(29+55+13) yd. (2+1+1) ft. (11+10+3) in.=97 yd. 4 ft. 24 in.=97 yd. (3+1) ft. (12+12) in.=98 yd. 3 ft.=99 yd.


d. 4,839 sq. yd. 8 sq. ft. 139 sq. in. + 7 sq. ft. 124 sq. in.=4,839 sq. yd. (8+7) sq. ft. (139+124) sq. in.=4,839 sq. yd. 15 sq. ft. 263 sq. in. =
4,839 sq. yd. 15 sq. ft. (144+119) sq. in.=4,839 sq. yd. 16 sq. ft. 119 sq. in.=4,839 sq. yd. (9+7) sq. ft. 119 sq. in.=4,840 sq. yd. 7 sq. ft. 119 sq. in.

4 0

3 years ago

Urgent answer with steps

exis [7]

It is a positive correlation because the weight of the puppy increases as the days increase

5 0

3 years ago

The gypsy moth is a serious threat to oak and aspen trees. A state agriculture department places traps throughout the state to d

k0ka [10]

Part A:

From the central limit theorem, since the number of samples is large enough (up to 30), the mean of the the mean of the average number of moths in 30 traps is 0.6.

Part B:

The standard deviation is given by the population deviation divided by the square root of the sample size.

$standard \ deviation= \frac{\sigma}{\sqrt{n}} = \frac{0.4}{\sqrt{30}} = \frac{0.4}{5.477} =0.073$

Part C:

The probability that an approximately normally distributed data with a mean, μ, and the standard deviation, σ, with a sample size of n is greater than a number, x, given by

$P(X\ \textgreater \ x)=1-P(X\ \textless \ x) \\ \\ =1-P\left(z\ \textless \ \frac{x-\mu}{\sigma/\sqrt{n}} \right)$

Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that the average number of moths in 30 traps is greater than 0.7 given by:

$P(X\ \textgreater \ 0.7)=1-P(X\ \textless \ 0.7) \\ \\ =1-P\left(z\ \textless \ \frac{0.7-0.6}{0.073} \right)=1-P(z\ \textless \ 1.369) \\ \\ =1-0.91455=\bold{0.0855}$

7 0

4 years ago

HELP. i need somebody help. not just anybody help. srysly tho....help

Alex17521 [72]

Answer:

300m meters

Step-by-step explanation:

multiply length value by 1000

7 0

3 years ago

Read 2 more answers

Find the equilibrium quantity and equilibrium price for the commodity whose supply and demand functions are given.

expeople1 [14]

Rewriting the two equations:

[Supply] $p = q^2+20$
[Demand] $p=-4q^2+10q+18600$

Equilibrium price is when
Supply = Demand
$q^2+20 = -4q^2+10q+18600$
$q^2+4q^2+20-10q-18600 = 0$
$5q^2-10q-18580=0$ ⇒ Simplifying the equation by dividing each term by 5

$q^2-2q-3716=0$

The simplified equation is in quadratic form.
There are three main methods for solving a quadratic equation: factorizing, completing the square, or quadratic formula.

Using the formula, we need the value of a, b, and c which is the constant of the quadratic equation.
$q_1= \frac{-b+ \sqrt{(b)^2-4ac)} }{2a}$ , and $q_2= \frac{-b- \sqrt{(b)^2-4ac)} }{2a}$

We have a = 1, b = -2, and c = -3716
Substituting these values into the formula we have
$q_1= \frac{-(-2)+ \sqrt{(-2)^2-4(1*-3716)} }{2} =61.97$
$q_2= \frac{-(-2)- \sqrt{(-2)^2-4(1*-3716)} }{2} =-59.97$

Since 'q' represents a quantity, we can't have negative values, so we choose the value of 'q' to be 61.97 ≈ 62 (rounded to the nearest whole number)

Answer: Equilibrium quantity = 62

4 0

3 years ago