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Sholpan [36]
3 years ago
15

a baker makes 5 apple pies for every 3 blueberry pies. last week the baker made 15 blueberry pies. how many apple pies did the b

aker make?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
6 0
Divide 15 by 3 then multiply that number by 5.
15/3=5
5 x 5 = 25 apple pies.

think of it like this:
How many small groups of [3 blueberry pies] was in the group of 15. the answer is 5. so if the baker makes 5 for every three, and there are 5 threes, then there will be 25 apple pies. because 5 times 5 is 25.
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Simplify the following fraction 15/35
notsponge [240]
Divide both sides by 5:
simplified = 3/7

Hope this helps!
8 0
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WhaThe factorization of x2 + 3x – 4 is modeled with algebra tiles.t is the factored form of x2 – x – 2?
Nataly [62]

Answer:

  x^2 -x -2 = (x -2)(x +1)

Step-by-step explanation:

To factor x^2 -x -2, you look for factors of -2 that have a sum of -1:

  -2 = (-1)(2) = (1)(-2) . . . . . the latter pair has a sum of -1

Then these are the constants in the binomial factors:

  x^2 -x -2 = (x +1)(x -2)

_____

<em>Comment on the question</em>

The fact that x^2 +3x -4 is modeled with algebra tiles seems to be irrelevant to the question that is actually asked.

4 0
3 years ago
Which property was used to simplify the expression?
Alex Ar [27]
Inverse Property, I am pretty sure. Not sure though.
7 0
2 years ago
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Factor completely and find the roots of the following . X^2-6x+8=0
LiRa [457]

Answer:

x =2, x = 4

Step-by-step explanation:

x^2 - 6x + 8 = 0

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5 0
3 years ago
A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou
valkas [14]

Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

p_v represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

6 0
3 years ago
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