1 easy
x=1x
if you have a cow, how many do you have? 1
if ou have an x, how many do you have? 1
1 is coeficinet
Keywords:
<em>equation, variable, clear, round, centesima, neperian logarithm, exponential
</em>
For this case we have the following equation 
, from which we must clear the value of the variable "x" and round to the nearest hundredth. To do this, we must apply properties of neperian and exponential logarithms. By definition:
So:
We apply Neperian logarithm to both sides:
We divide between "3" both sides of the equation:
Rounding out the nearest hundredth we have:
Answer:
A million seconds is not that long. My next birthday is in 1,296,000 seconds
from now, and I have already lived more than 2.3 billion seconds !
(1,000,000 seconds) x (1 day / 86,400 seconds) =
11days 13hours 46minutes 40seconds .
It's possible that you might have one birthday within that length of time,
but it's not guaranteed. It would have to be the RIGHT million seconds.
If that's been your whole life so far ... you are 1 million seconds old ..,
then you have not had your first birthday yet.
Answer:
h ≈ 7.816 cm
r ≈ 5.527 cm
Step-by-step explanation:
The volume of a cone is:
V = ⅓ π r² h
The lateral surface area of a cone is:
A = π r √(r² + h²)
1/4 of a liter is 250 cm³.
250 = ⅓ π r² h
h = 750 / (π r²)
Square both sides of the area equation:
A² = π² r² (r² + h²)
Substitute for h:
A² = π² r² (r² + (750 / (π r²))²)
A² = π² r² (r² + 750² / (π² r⁴))
A² = π² (r⁴ + 750² / (π² r²))
Take derivative of both sides with respect to r:
2A dA/dr = π² (4r³ − 2 × 750² / (π² r³))
Set dA/dr to 0 and solve for r.
0 = π² (4r³ − 2 × 750² / (π² r³))
0 = 4r³ − 2 × 750² / (π² r³)
4r³ = 2 × 750² / (π² r³)
r⁶ = 750² / (2π²)
r³ = 750 / (π√2)
r³ = 375√2 / π
r = ∛(375√2 / π)
r ≈ 5.527
Now solve for h.
h = 750 / (π r²)
h = 750 / (π (375√2 / π)^⅔)
h = 750 ∛(375√2 / π) / (π (375√2 / π))
h = 2 ∛(375√2 / π) / √2
h = √2 ∛(375√2 / π)
h ≈ 7.816
Notice that at the minimum area, h = r√2.
