Answer:
19/8
Step-by-step explanation:
8x-7=-12
8x=19
x=19/8
Answer:
The amount of the loan is $120,000 -10% + 2% = $110,400, assuming the "points" are added to the financed amount.
I find that the monthly payment will be
$848.89. There will be 360 such payments over 30 years, for a total payment amount of $30The amount of the loan is $120,000 -10% + 2% = $110,400, assuming the "points" are added to the financed amount.
R = Pi/[1 - (1+i)^(-n)] where
P = 110,400
R = the monthly payment
i = 8.5/[100(12)] = .007083...
n = 30(12) = 360 yielding
R = $848.88 per month.
Therefore, the total interest paid is 360(848.88) - 100,400.
5,600. Subtract the original principle (110,400) from that to get the interest paid.
hopes this helps :]
Answer:
D. y - 7 = -4 (x - 2)
Step-by-step explanation:
y - 7 = -4 (x - 2)
that is what the line will look like.
We want to compute
![\dfrac{-5x^4+4x^3-20x^2+15x-16}{-x^2-3}](https://tex.z-dn.net/?f=%5Cdfrac%7B-5x%5E4%2B4x%5E3-20x%5E2%2B15x-16%7D%7B-x%5E2-3%7D)
The goal is to write it in the following form:
![-5x^4+4x^3-20x^2+15x-16=Q(x)(-x^2-3)+R(x)](https://tex.z-dn.net/?f=-5x%5E4%2B4x%5E3-20x%5E2%2B15x-16%3DQ%28x%29%28-x%5E2-3%29%2BR%28x%29)
First step: How many "copies" of
does
contain? We can write
, so the answer is
copies.
If we distribute
to
, we get
![5x^2(-x^2-3)=-5x^4-15x^2](https://tex.z-dn.net/?f=5x%5E2%28-x%5E2-3%29%3D-5x%5E4-15x%5E2)
If we were done, then this product would have matched the numerator at the start. But it doesn't; there are still some terms that need to vanish. In particular, we still have to account for
![(-5x^4+4x^3-20x^2+15x-16)-(-5x^4-15x^2)=4x^3-5x^2+15x-16](https://tex.z-dn.net/?f=%28-5x%5E4%2B4x%5E3-20x%5E2%2B15x-16%29-%28-5x%5E4-15x%5E2%29%3D4x%5E3-5x%5E2%2B15x-16)
Second step: How many copies of
can we find in
? Well,
, so the answer is
. Then
![(5x^2-4x)(-x^2-3)=-5x^4+4x^3-15x^2+12x](https://tex.z-dn.net/?f=%285x%5E2-4x%29%28-x%5E2-3%29%3D-5x%5E4%2B4x%5E3-15x%5E2%2B12x)
but this still doesn't match the original numerator. We still have to deal with
![(-5x^4+4x^3-20x^2+15x-16)-(5x^2-4x)(-x^2-3)=-5x^2+3x-16](https://tex.z-dn.net/?f=%28-5x%5E4%2B4x%5E3-20x%5E2%2B15x-16%29-%285x%5E2-4x%29%28-x%5E2-3%29%3D-5x%5E2%2B3x-16)
Third step: How many copies of
can we get out of
?
. Then
![(5x^2-4x+5)(-x^2-3)=-5x^4+4x^3-20x^2+12x-15](https://tex.z-dn.net/?f=%285x%5E2-4x%2B5%29%28-x%5E2-3%29%3D-5x%5E4%2B4x%5E3-20x%5E2%2B12x-15)
This also doesn't match the original numerator. We have a difference between what we have and what we want of
![(-5x^4+4x^3-20x^2+15x-16)-(5x^2-4x+5)(-x^2-3)=3x-1](https://tex.z-dn.net/?f=%28-5x%5E4%2B4x%5E3-20x%5E2%2B15x-16%29-%285x%5E2-4x%2B5%29%28-x%5E2-3%29%3D3x-1)
But we also can't divide
into chunks of
, and we can't continue the division algorithm.
Our final answer would be
![\dfrac{-5x^4+4x^3-20x^2+15x-16}{-x^2-3}=5x^2-4x+5+\dfrac{3x-1}{-x^2-3}](https://tex.z-dn.net/?f=%5Cdfrac%7B-5x%5E4%2B4x%5E3-20x%5E2%2B15x-16%7D%7B-x%5E2-3%7D%3D5x%5E2-4x%2B5%2B%5Cdfrac%7B3x-1%7D%7B-x%5E2-3%7D)
For the second problem, you should find
![\dfrac{-15x^3-13x+4}{5x^2+2}=-3x+\dfrac{-7x+4}{5x^2+2}](https://tex.z-dn.net/?f=%5Cdfrac%7B-15x%5E3-13x%2B4%7D%7B5x%5E2%2B2%7D%3D-3x%2B%5Cdfrac%7B-7x%2B4%7D%7B5x%5E2%2B2%7D)