Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer: the distance from one corner of the field to the other corner is 136 m
Step-by-step explanation:
The distance from one corner to the other corner is the diagonal and it
divides the field into two equal right angle triangles. The diagonal represents the hypotenuse of each right angle triangle. The length and width of the rectangle represents the adjacent and opposite sides of the right angle triangle. To determine the length of the diagonal, d, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Therefore
d² = 110² + 80²
d² = 12100 + 6400 = 18500
d = √18500
d = 136 meters
Answer:
so easy and obvious dude
Step-by-step explanation:
An obtuse triangle is a triangle which has one obtuse angle. <span>
Obviously, only a single angle in a </span>triangle<span> can be </span>obtuse<span> or it wouldn't be a </span>triangle.
Hope that helps you
40.75 - 7.05= 33.7
33.7 / 2 = 16.85
16.85 ft. should be on each side of the 7.05 ft. bench
