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Anna71 [15]
3 years ago
14

How do I solve this?

Mathematics
2 answers:
dlinn [17]3 years ago
8 0
If there is a minus symbol inside the root you should take imaginary root

kirill115 [55]3 years ago
5 0

Rewrite -32 as( -2)^5 5squareroot (-2)^5  Assume positive real numbers   You will get -2

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-90 = -100 + x help need answer
d1i1m1o1n [39]

Answer:

10 =x

Step-by-step explanation:

-90 = -100 + x

Add 100 to each side to isolate x

-90+100 = -100+100 + x

10 =x

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3 years ago
True or false: is ST parallel to PR? (photo above)
Deffense [45]

Answer:

true

Step-by-step explanation:

5 0
3 years ago
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-54 °c converted to kelvin is k.
Agata [3.3K]
T_{[K]}=t_{[^oC]}+273.15\\\\t_{[^oC]}=-54\\\\subtitute\\\\T_{[K]}=-54+273.15=219.15\approx219\\\\Answer:\boxed{-54^oC=219.15K\approx219K}
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I really need help someone
Ann [662]

with what english, science anything i no it all

8 0
3 years ago
Find an equation for those points P such that the distance from P to A(0, 1, 2) is equal to the distance from P to B(6, 4, 2). W
suter [353]

Answer:  The required equation for points P is 4x+2y=17.

Step-by-step explanation: We are give two points A(0, 1, 2) and B(6, 4, 2).

To find the equation for points P such that the distance of P from both A and B are equal.

We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.

Let the point P be represented by (x, y, z).

According to the given information, we have

PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.

Thus, the required equation for points P is 4x+2y=17.

8 0
3 years ago
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