All categories

3 years ago

When evaluating the expression 5x^2 for x=4 explain why 4 must be squared before multiplying by 5

Mathematics

1 answer:

fenix001 [56]3 years ago

3 0

Answer:

Order of operations

Step-by-step explanation:

4 must be squared before multiplying by 5 because of order of operations (PEMDAS). PEMDAS stands for parentheses, exponents, multiplication, division, addition, and subtraction. 4 squared is an example of an exponent and multiplying by 5 is an example of multiplication. Therefore 4 squared must come first.

When 4 is squared first, you will get an answer of 80.

When you multiply by 5 first, you will get an answer of 400.

You might be interested in

Evaluate (3x + 8) when d x = 3.

daser333 [38]

Step-by-step explanation:

Given in the pic.

Have a good day!

6 0

3 years ago

Consider the graphed function. 100POINTS!!!!

Sati [7]

Answer:

Domain -5 ≤x<1

Range -4 ≤y<7

Step-by-step explanation:

The domain is the values that x takes

X goes from -5 included to 1 not included

-5 ≤x<1

The range is the values that y takes

y goes from -4 included to 7 not included

-4 ≤y<7

4 0

3 years ago

Which expression is equivalent to 5y^-3

Alex787 [66]

(5y - 3)(2y + 5) = 10y² + 25y - 6y - 15

= 10y² + 19y - 15

4 0

4 years ago

Karen buys apples and bananas for the daycare center she runs. The apples cost $1.50 per pound, and the bananas are $0.50 per po

asambeis [7]

Answer:

1.50x+0.50y≤20.50

Step-by-step explanation:

its the plato answer.

4 0

3 years ago

The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest

jeka94

Answer:

(a) The probability that the port handles less than 5 million tons of cargo per week is 0.7291.

(b) The probability that the port handles 3 or more million tons of cargo per week is 0.9664.

(d) The number of tons of cargo per week that will require the port to extend its operating hours is 5.35 million tons.

Step-by-step explanation:

Let X = amount of cargo the port handles per week.

The random variable X is Normally distributed with parameters,

μ = 4.5 million

σ = 0.82 million

(a)

Compute the probability that the port handles less than 5 million tons of cargo per week as follows:

$P(X$

*Use a z-table for the probability.

Thus, the probability that the port handles less than 5 million tons of cargo per week is 0.7291.

(b)

Compute the probability that the port handles 3 or more million tons of cargo per week as follows:

$P(X\geq 3)=P(\frac{X-\mu}{\sigma}\geq \frac{3-4.5}{0.82})\\=P(Z>-1.83)\\=P(Z$

*Use a z-table for the probability.

Thus, the probability that the port handles 3 or more million tons of cargo per week is 0.9664.

(c)

Compute the probability that the port handles between 3 million and 4 million tons of cargo per week as follows:

$P(3$

Thus, the probability that the port handles between 3 million and 4 million tons of cargo per week is 0.2373.

(d)

It is provided that P (X < x) = 0.85.

Then, P (Z < z) = 0.85.

The value of z for this probability is:

z = 1.04.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\1.04=\frac{x-4.5}{0.82}\\x=4.5-+1.04\times 0.82)\\x=5.3528\approx5.35$

Thus, the number of tons of cargo per week that will require the port to extend its operating hours is 5.35 million tons.

5 0

4 years ago