(-2,6) (5,-8)
slope = (y2 - y1) / (x2 - x1)
slope = (-8 - 6) / (5 - (-2) = -14/7 = -2 <==
midpoint = (x1 + x2)/2 , (y1 + y2)/2
m = (-2 + 5)/2 , (6 - 8)/2
m = (3/2, -1) <===
distance = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((5 - (-2)^2 + (-8 - 6)^2)
d = sqrt ((5 + 2)^2 + (-14^2))
d = sqrt (7^2 + 14^2)
d = sqrt (49 + 196)
d = sqrt 245
d = 15.65 <==
The answer is B and C. The atmospheric pressure is 14lb/in2 and As the altitude approaches sea level, the atmospheric pressure increases.
Answer:
ASA
Step-by-step explanation:
In given triangle
Line BC = Line QR
Angle ABC = Angle PQR
Angle ACB = Angle PRQ
Computation:
Angle ABC = Angle PQR (Angle)
Line BC = Line QR (Side)
Angle ACB = Angle PRQ (Angle)
So,
ΔABC ≅ ΔPQR
By Angle Side Angle property
ASA
Answer:
8x + 1/2 or 8x + 0.5
Step-by-step explanation:
-6x + 3 3/4 + 14x - 3.25
u can either convert the fraction to a decimal or convert the decimal into a fraction, i'm going to do the latter
-6x + 3 3/4 + 14x - 3 1/4
rearrange to make it easier, don't need to do this i'm just doing this for the sake of it
-6x + 14x + 3 3/4 - 3 1/4
8x + 2/4, simplify this
8x + 1/2
The decimal way if u want:
-6x + 3 3/4 + 14x - 3.25
-6x + 3.75 + 14x - 3.25
-6x + 14x + 3.75 - 3.25
8x + 0.5
Remember the distance formula
