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bezimeni [28]
4 years ago
9

Solve for x for the linear pairs.

Mathematics
1 answer:
FrozenT [24]4 years ago
8 0

Answer:

X = 13

Step-by-step explanation:

Since this is a linear pair, it equals to 180 degrees.

7x + 37 + 4x = 180

11x + 37 = 180

-37 -37

11x = 143

11x/11 = 143/11

x = 13

Good luck on your form!

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Fill in the blanks please. spamming wrong or absurd answers to get points will be reported and you won't get any points in the e
Monica [59]
I’m doing the same thing right now, idk the last 2 but the first few are Pythagorean theorem, substitution, substitution property of equality, and square root property of equality

Good luck!!!
3 0
4 years ago
Alexis has a savings account that earns 2.1% interest compounded daily. If she opened the account 17 years ago with a deposit of
sergejj [24]

Compound Interest Formula:  A = P(1 + r/n)^(n·t)

A = final amount                  r = rate, as a decimal (.021)                      t = number of years (17)

P = initial amount (2914.72)    n = number of times compounded per year (365)

A  =  2914.72(1 + .021/365)^(365·17)  =  $4165.20

Interest earned:  $4165.20 - $2914.72  =  $1250.48           <-----  Answer

You might want to recalculate this, attempting to handle leap years, by replacing the number of times compounded per year with 365.25 and see if that has an effect

5 0
3 years ago
If g(x)=3x-2, find g(8)-g(-5)
Brut [27]
<h2>Answer:</h2>g(8)-g(-5)=39

<h2>Explanations:</h2>

Given the function

g(x)=3x-2

Get g(8) by substituting x = 8 into the function;

\begin{gathered} g(8)=3(8)-2 \\ g(8)=24-2 \\ g(8)=22 \end{gathered}

Get g(-5) by substituting x = -5 into the function

\begin{gathered} g(-5)=3(-5)-2 \\ g(-5)=-15-2 \\ g(-5)=-17 \end{gathered}

Take the difference in the result to have;

\begin{gathered} g(8)-g(-5) \\ =22-\mleft(-17\mright) \\ =22+17 \\ =39 \end{gathered}

Hence the difference between the given functions is 39

6 0
1 year ago
The area of a rectangular parking lot is represented by A = 6x^2 − 19x − 7 If x represents 15 m, what are the length and width o
Mekhanik [1.2K]

Answer:

The length and width of the parking lot are \frac{46}{3} meters and \frac{23}{2} meters, respectively.

Step-by-step explanation:

The surface formula (A) for the rectangular parking lot is represented by:

A = w\cdot l

Where:

w - Width of the rectangle, measured in meters.

l - Length of the rectangle, measured in meters.

Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If A = 6\cdot x^{2}-19\cdot x -7, the factorized form is:

A = \left(x-\frac{7}{2}\,m \right)\cdot \left(x+\frac{1}{3}\,m \right)

Now, let consider that w = \left(x-\frac{7}{2}\,m \right) and l = \left(x+\frac{1}{3}\,m \right), if x = 15\,m, the length and width of the parking lot are, respectively:

w =\left(15\,m-\frac{7}{2}\,m \right)

w = \frac{23}{2}\,m

l =\left(15\,m+\frac{1}{3}\,m \right)

l = \frac{46}{3}\,m

The length and width of the parking lot are \frac{46}{3} meters and \frac{23}{2} meters, respectively.

5 0
3 years ago
Write two expressions with unlike denominators whose sum is x-3/x+2, I need help it is confusing for me.
skad [1K]

Answer:

\displaystyle A=\frac{x-2}{x+3}

\displaystyle B=\frac{-5}{(x+3)(x+2)}

Step-by-step explanation:

We need to find two expressions with unlike denominators what sum

\displaystyle S=\frac{x-3}{x+2}

Let's suppose one of the expressions is:

\displaystyle A=\frac{x-2}{x+3}

Now we subtract S minus A to find the other expression B:

\displaystyle B=S-A=\frac{x-3}{x+2}-\frac{x-2}{x+3}

Multiply the first fraction by x+3 and the second by x+2;

\displaystyle B=(x+3)\frac{x-3}{(x+3)(x+2)}-(x+2)\frac{x-2}{(x+3)(x+2)}

Operating:

\displaystyle B=\frac{x^2-9}{(x+3)(x+2)}-\frac{x^2-4}{(x+3)(x+2)}

Subtracting both fractions with like denominators:

\displaystyle B=\frac{x^2-9-(x^2-4)}{(x+3)(x+2)}

Simplifying:

\displaystyle B=\frac{-5}{(x+3)(x+2)}

Thus the two expressions are:

\displaystyle A=\frac{x-2}{x+3}

And

\displaystyle B=\frac{-5}{(x+3)(x+2)}

8 0
3 years ago
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