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ELEN [110]
3 years ago
5

Given 2 points (-2,6) and (5,-8) what is the slope, distance, and midpoint

Mathematics
1 answer:
Anastasy [175]3 years ago
5 0
(-2,6) (5,-8)

slope = (y2 - y1) / (x2 - x1)
slope = (-8 - 6) / (5 - (-2) = -14/7 = -2 <==

midpoint = (x1 + x2)/2 , (y1 + y2)/2
m = (-2 + 5)/2 , (6 - 8)/2
m = (3/2, -1) <===

distance = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((5 - (-2)^2 + (-8 - 6)^2)
d = sqrt ((5 + 2)^2 + (-14^2))
d = sqrt (7^2 + 14^2)
d = sqrt (49 + 196)
d = sqrt 245
d = 15.65 <==
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Mr. Chen writes the expression 4 ×
telo118 [61]

Answer:

4*(7-2)2÷10

=4*5*1/5

=20/5

=4

Step-by-step explanation:

3 0
3 years ago
Evaluate -a -8b when a = 9 and b = -3<br> someone please help quick!!
ollegr [7]

Answer:

15

Step-by-step explanation:

-a -8b = -9 + 24 = 15

4 0
3 years ago
Read 2 more answers
Given that ABCD is a rhombus, find the value of x.<br> (X+14)
Kay [80]

Answer:

option B. x=38^o

Step-by-step explanation:

we know that

1) The two diagonals of a rhombus are perpendicular

2) The sum of the interior angles in any triangle must be equal to 180 degrees

Let

O ----> the intersection point of the diagonals of the rhombus

In the right triangle OAD

x^o+(x+14)^o+90^o=180^o

solve for x

x^o+(x+14)^o=90^o

2x=90^o-14^o

2x=76^o

x=38^o

6 0
3 years ago
Haley works at a candy store. There are 10 types of bulk candy. Find the probability that one type of candy will be chosen more
DIA [1.3K]

Answer:

Probability that one type of candy will be chosen more than once in 10 trials = 0.2639

Step-by-step explanation:

This is a binomial experiment because

- A binomial experiment is one in which the probability of success doesn't change with every run or number of trials.

- It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (10 trials, with the outcome of each trial being that we get the required candy or not)

- The outcome of each trial/run of a binomial experiment is independent of one another.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 10 trials

x = Number of successes required = number of times we want to pick a particular brand of candy = more than once, that is > 1

p = probability of success = probability of picking a particular brand of candy from a bulk with 10 different types of candies = (1/10) = 0.10

q = probability of failure = Probability of not picking our wanted candy = 1 - p = 1 - 0.1 = 0.90

P(X > 1) = 1 - P(X ≤ 1)

P(X ≤ 1) = P(X = 0) + P(X = 1)

P(X = 0) = ¹⁰C₀ (0.10)⁰ (0.90)¹⁰⁻⁰ = 0.3486784401

P(X = 1) = ¹⁰C₁ (0.10)¹ (0.90)¹⁰⁻¹ = 0.387420489

P(X ≤ 1) = 0.3486784401 + 0.387420489 = 0.7360989291

P(X > 1) = 1 - 0.7360989291 = 0.2639010709 = 0.2639

Hope this Helps!!!

5 0
3 years ago
Need help kinda stuck on this one!
irinina [24]
It goes zero positive negative. that is from left to right
6 0
2 years ago
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