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Fudgin [204]
3 years ago
12

PLEASE HELP WILL GIVE BRAINLYIST TO FIRST PERSON

Chemistry
1 answer:
kolezko [41]3 years ago
5 0

Answer:

1) Weak base.

2) Weak acid.

Explanation:

<em>1) Which would have a lower pH, a 0.1 M solution of a strong base or a weak base? Why?</em>

  • For bases:

Solution with lower pH means that the solution has a lower basic character.

While solution with higher pH means that the solution has a higher basic character.

When we have a 0.1 M solution of a strong base or a weak base, the weak base will have a lower pH because it is not completely dissociated to produce OH⁻ ions.

While, strong base dissociates completely to produce OH⁻ ions, so it will has higher basic character and thus has a higher pH value.

So, weak base will have the lower pH value.

<em>2) Which would have a higher pH, a 0.1 M solution of a strong acid, or a weak acid? Why?</em>

<em></em>

  • For Acids:

Solution with lower pH means that the solution has a higher acidic character.

While solution with higher pH means that the solution has a lower acidic character.

When we have a 0.1 M solution of a strong acid or a weak acid, the weak acid will have a higher pH because it is not completely dissociated to produce H⁺ ions, so it has a lower acidic character.

While, strong acid dissociates completely to produce H⁺ ions, so it will has higher acidic character and thus has a lower pH value.

So, weak acid will have the higher pH value.

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Explanation:

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3 years ago
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Answer:

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3 years ago
A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

                           M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH  = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

5 0
3 years ago
Convert 567 kg to grams
kodGreya [7K]
567000 would be in grams, hope this helps :)
8 0
3 years ago
Read 2 more answers
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