All categories

3 years ago

Name of molecule formed upon oxidation of aldehyde to carbonyl group

1 answer:

6 0

Aldehyde is a group of organic compounds with the general form of RCHO. Oxidation of aldehyde can lead to the formation of the carboxylic acids, with the general form of RCO₂H.

With this oxidation, the typical reagents promoting the oxidation are chromic acids, chromate salts, permanganate, etc.

You might be interested in

What was the initial temperature of a gas contained in a 2.0-L bottle at a pressure of 1.00 atm if it was placed under vacuum an

lesya692 [45]

V1/T1 = V2/T2

Substitute the value use ratio and proportion. Use calculator.

V1 = (V2 x T1) / T2

1 is initial, 2 is final

4 0

3 years ago

photosynthesis in plants require chloroplasts and light energy. identify two materials plants also use in this process

Nataliya [291]

I would assume carbon and water if not Im sorry.

5 0

3 years ago

If an ice cube weighing 25.0 g with an initial

riadik2000 [5.3K]

Answer:

∘

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

∘

to liquid at

∘

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

−

(

)

, where

- the heat absorbed by the solid at

∘

- the heat absorbed by the liquid at

∘

- the heat lost by the warmer water sample

The two equations that you will use are

⋅

, where

- heat absorbed/lost

- the mass of the sample

- the specific heat of water, equal to

4.18

∘

- the change in temperature, defined as final temperature minus initial temperature

and

⋅

fus

, where

- heat absorbed

- the number of moles of water

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

⋅

1 mole H

18.015

5.551 moles H

So, how much heat is needed to allow the sample to go from solid at

∘

to liquid at

∘

5.551

moles

⋅

6.01

mole

33.36 kJ

This means that equation

(

)

becomes

33.36 kJ

−

The minus sign for

is used because heat lost carries a negative sign.

So, if

is the final temperature of the water, you can say that

33.36 kJ

sample

⋅

sample

−

water

⋅

water

More specifically, you have

33.36 kJ

100.0

⋅

4.18

∘

⋅

(

−

)

∘

−

650

⋅

4.18

∘

⋅

(

−

)

∘

33.36 kJ

418 J

⋅

(

−

)

−

2717 J

⋅

(

−

)

Convert the joules to kilojoules to get

33.36

0.418

⋅

−

2.717

⋅

(

−

)

This is equivalent to

0.418

⋅

2.717

⋅

67.925

−

33.36

34.565

0.418

2.717

11.026

∘

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

∘

Explanation:

3 0

2 years ago

(10 points) easy WILL GIVE BRAINLIEST

nignag [31]

Answer:

Both b/c a chemical formula tells you how many and a sketch formula shows how they are bonded together.

Molecular formulas show how many atoms of each element one molecule of a compound contains. Note: Ionic compounds are generally crystalline solids with high melting points. Other compounds, however, have very different properties.

4 0

2 years ago

Read 2 more answers

Lead (ll) nitride+ammonium sulfate > lead(ll) sulfate + ammonium nitride

Alenkinab [10]

Answer:

$Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N$

Explanation:

Let's rewrite the given word equation in its chemical balanced equation representation:

1. Lead(II) nitride is represented by lead, Pb, in an oxidation state of 2+, while nitride is a typical nitrogen anion with a state 3-. As a result, the lowest common multiple between 2 and 3 is 6, meaning 2 lead cations are needed to balance 3 nitrogen anions: $Pb_3N_2$ .

2. Ammonium sulfate consists of an ammonium cation with a 1+ charge and sulfate anion with a 2- charge, two ammonium cations needed: $(NH_4)_2SO_4$ .

3. Lead(II) sulfate would have one lead cation and one sulfate anion, as they have the same magnitude of charges with opposite signs: $PbSO_4$ .

4. Ammonium nitride would require three amonium cations to balance the nitride anion: $(NH_4)_3N$ .

Let's write the balanced equation:

$Pb_3N_2 + 3 (NH_4)_2SO_4\rightarrow 3 PbSO_4 + 2 (NH_4)_3N$

7 0

3 years ago