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4 years ago

What's the name for excessive bodily hair growth in women?

Chemistry

2 answers:

bulgar [2K]4 years ago

8 0

I believe its called Hirsutism but I can't be sure.

maw [93]4 years ago

5 0

I believe it's Hirsutism, maybe list options if there are any next time! :)

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PLEASE HELP I WILL GIVE BRAINLIEST

stellarik [79]

Answer: YES!

Explanation:

Ox2 Co2 Hydrogen and Corossion 3

3 0

3 years ago

Americium-241 is an alpha emitter used in household smoke detectors and K-40 is a positron emitter used to date rock samples. Th

VMariaS [17]

Answer:

Np-237, Ar-40.

Explanation:

Alpha particle is positively charged particle having a mass of 4 unit. Hence,when alpha is removed from any isotope it produces a element having mass 4 units less than original isotope that was before emission. Americium 241 isotopes used in the smoke detector which emit an alpha particle to produce neptunium-237.

Potassium-40 emits positron which is having negative charge to lower one proton and increase one neutron number in the particle and in such way it will produce $^{40}Ar_{18}$ not $^{40}Ca_{20}$

4 0

3 years ago

Read 2 more answers

Which one IS an example of a homogenous mixture?

elena-s [515]

Answer:

I think option ( b) tea is right answer

8 0

3 years ago

What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?

Naddika [18.5K]

Answer:

32.5 moles of O2(g) are necessaries for a complete reaction

Explanation:

Based on the reaction of combustion of C4H10(g):

C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.

That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:

5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =

32.5 moles of O2(g) are necessaries for a complete reaction

4 0

3 years ago

An electrolytic cell transferred 0.10 m o l of electrons when a constant current of 2.0 A was applied. How many hours did this t

marusya05 [52]

Answer:

1.34 hr

Explanation:

From the question given above, the following data were obtained:

Number of mole of electron (e) = 0.1 mole

Current (I) = 2 A

Time (t) =?

Next, we shall determine the quantity of electricity transferred. This can be obtained as follow:

1 mole of electron = 96500 C

Therefore,

0.1 mole of electron = 0.1 × 96500

0.1 mole of electron = 9650 C

Thus, 9650 C of electricity was transferred.

Next, we shall determine the time. This can be obtained as follow:

Current (I) = 2 A

Quantity of electricity (Q) = 9650 C

Time (t) =?

Q = It

9650 = 2 × t

Divide both side by 2

t = 9650 / 2

t = 4825 s

Finally, we shall convert 4825 s to hour. This can be obtained as follow:

3600 s = 1 hr

Therefore,

4825 s = 4825 s× 1 hr / 3600 s

4825 s = 1.34 hr

Thus, the time taken is 1.34 hr

3 0

3 years ago