The answer is 144 over 13
Sin < C = 63/65 so m < C = 75.75 degrees
and tan B = 16/63 so m <B = 14.25 degrees
m < C + m<B = 75.75 + 14.25 = 90 degrees
Therefore m < A = 180-90 = 90
therefore the triangle is right-angled.
3/5 = 0.6
0.15 = 3/20
7/8 = 0.875
0.725 = 29/40
<span>if you have 21 bins then the 'middle bin' is bin 11 (starting at 1)
So the 'mean' of this distribution is 11.
The SD is 3
so using the above calculator (or your own tables ) you get that the probability of a ball being in bin 7 or less is .091
A is you answer
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Answer: P = 1/7
Explanation:
There 35 students total and there are 3 students with grade D and 2 students with Grade F
3/35 + 2/35 = 5/35 = 1/7
