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belka [17]
3 years ago
11

1 4 Joey enlarged a 3-inch by 5-inch photograph on a copy machine. He enlarged it four times. The table below shows

the area of the photograph after each enlargement
Enlargement
2 3
Area (square inches) 15 18.8 23.4 29.3 36.6
What is the average rate of change of the area from the original photograph to the fourth enlargement, to the
nearest tenth
1) 43
3) 5.4
2) 4.5
4) 6.0

Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

3) 5.4

Step-by-step explanation:

Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:

[f(x2) - f(x1)]/[x2 - x1]

From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:

[36.6 - 15]/[4 - 0] = 5.4

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A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
2 years ago
George has a small coin collection.  He has collected 16 gold coins, 28 silver coins, 32 copper coins, and4 bronze coins. At a f
romanna [79]
<em>Total number of coin that George has
16 + 28 + 32 + 4 = 80 coins
total number of coins sold by George
= 15% of 80
= 15/100 X 80
= 12 coins             (ans)</em>
8 0
3 years ago
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If 3 pieces of candy cost $2.10, how much would 8 pieces cost
Alex_Xolod [135]

Answer: 5.60

Step-by-step explanation: Divide 2.10 by 3. You get 0.7. Then multiply 0.7 by 8 and you get 5.60.

8 0
3 years ago
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Surface area of a half pipe if it is 7m
Monica [59]

Answer:

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7 0
3 years ago
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(40 pts)can you factor the difference of square?perfect square trinomials?
stira [4]

Answer:

Step-by-step explanation:

The difference of two squares may be represented by the formula:  a^2-b^2,

which can be factored as (a+b)(a-b)

A perfect square trinomial may be represented by the formula: a^(2)-2ab+b^2 or  a^(2)+2ab+b^2, depending on the sign of b

if b is negative: use the formula a^(2)-2ab+b^2, which can be factored as (a-b)*(a-b) or (a-b)^(2)

if b is positive: use the formula a^(2)+2ab+b^2, which can be factored as (a+b)*(a+b) or (a+b)^(2)

7 0
3 years ago
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