Her school is 2/3 miles away
2/3=4/6miles
So we need to find out how long it will take for her to run home from school...
School=4/6 miles
In 1 minutes she can run 1/6 miles
1min=1/6miles
In 2 minutes she can run 1/6+1/6 miles (1/6+1/6=2/6)
2min=2/6miles
3min=3/6miles
4min=4/6miles
It will take Erica 4 minutes to run 4/6 miles, so it'll take her 4 minutes to get home.
I’m pretty sure that will be linear.
Remmber pemdas or gemdas or bodmas or whatever
exponential laws
(x^m)^n=x^(mn)
ok so
(3^2)(2a)^(3/2))^2=
(3^2)(2a)^((3/2)*2)=
(3^2)(2a))^(6/2)=
(3^2)(2a)^3=
(3^2)(8a^3)^3=
(9)(8a^3)=
72a^3
2nd one from left
1/4 is the amount of girls in 8th grade
hope its not too late
X=29 and y=10
You would isolate one of the variables and then plug the expression into the other equation to find the value of one variable. Then you would plug this value into the other equation to determine the value of the remaining variable.