<span>2y = x + 3 then x = 2y - 3
5y = x - 7 then x = 5y + 7
so
</span>2y - 3 = 5y + 7
2y - 5y = 7 + 3
-3y = 10
y = -10/3
y = -3 1/3
<span>2y = x + 3
</span>2 (-10/3) = x + 3
-20/3 - 3 =x
-29/3 = x
-9 2/3 =x
or
x = -9 2/3
solutions: x = -9 2/3 and y = -3 1/3
When the events are independent, the probability of both is the product of the probabilities of the individual events.
P(A∩B) = P(A)×P(B) = 0.7×0.8 =
D. 0.56
Step-by-step explanation:
(a)
ii.
21 - 5 = 16 play only chess.
iii.
23 - 5 = 18 play only cards
5 play both.
that is 16+18+5 = 39 that play at least one of these games.
i.
so, 45 - 39 = 6 don't play any of these games.
(b)
we have 16+18 = 34 pupils out of 45 that play exactly one game.
so the probabilty to pick one of them is as usual
desired cases / total cases = 34/45 =
= 0.755555555... ≈ 0.76
Answer:
y=
x-6.5
Step-by-step explanation:
= 
= 
y=mx+b
-8 = () (-6) +b
-8 = - 
+b
b= -6.5
m is 43
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