Answer:
31/11 yards
Step-by-step explanation:
area = lenght * width
31/2 = 11/2 * x
31 = 11 * x
x = 31/11
55x< 200 - 65 is the correct answer Answer : 55 is less than 200 minus 65
The marginal frequency for the people who do not like cantaloupe is StartFraction 91 Over 200 EndFraction/
The correct option is (C),
<h3>What is Marginal Relative frequency?</h3>
Marginal Relative Frequency is the ratio between the frequency of a row total or column total to the total frequency of the data.
Given:
Watermelon Not watermelon Total
Cantaloupe 93 16 109
Not cantaloupe 66 25 91
Total 159 41 200
Hence, the Marginal Relative frequency is = 91/200 = 0.455
Learn more about this concept here:
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Answer:
The two numbers following 1,-2,3,-4,5... are -6 and 7.
Step-by-step explanation:
index: 1 2 3 4 5 ....
value: 1 -2 3 -4 5
Let the index be n. Then the first term is a(1), the secon is a(2), and so on.
a(2) = 2*(-1)^(2-1) = 2*(-1) = -2 (correct)
a(3) = 3*(-1)^(3-1) = 3*(-1)^2 = 3 (correct)
a(4) = 4*(-1)^(4-1) = 4*(-1)^3 = -4 (correct)
So the general formula for a(n) is: a(n)=n(-1)^(n-1)
Thus,
a(5) = 5(-1)^4 = 5
a(6) = 6(-1)^5 = -6
a(7) = 7(-1)^6 = 7
The "next two numbers in the pattern" are -6 and 7. The first 7 numbers are
1,-2,3,-4,5, -6, 7
Answer:
It will take <u>3 hours</u> for 5 examiners to mark 80 papers.
Step-by-step explanation:
Given:
Time taken by an examiner to mark 80 exam papers = 15 hours
To find time taken by 5 examiners to mark 80 exam papers.
Solution:
Applying unitary method.
One examiner takes 15 hours to mark 80 exam papers
So, in one hour he can mark = papers
In hour 5 examiners can mark = papers
So, we know 5 examiners can mark papers in 1 hours.
So, to mark 1 paper they will take = = of a paper
Thus, to mark 80 papers they will take = hours.
Thus, it will take 3 hours for 5 examiners to mark 80 papers.