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Bad White [126]
3 years ago
15

Oneta writes an algebraic expression with three terms. The y-term has a coefficient of -3, and the x-term has a coefficient of 1

. The expression does not have a constant term. Which expression could she have written?
Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

1x - 3y + z

Step-by-step explanation:

Oneta has to write an algebraic expression with three terms without constant.

Given: The coefficient of x is 1 and the coefficient of y is -3.

so the possibilities are:

1x - 3y + z which is three term without constant.

1x - 3y - z which is three terms without constant.

Which represents three-dimensional figure.

Rina8888 [55]3 years ago
3 0
X - 3y + z

Another term would be the 3rd term which would be working with 3d planes instead of 2d planes.
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Explain how you know the quotients 540÷90 and 5,400 ÷ 900 are equal without doing any computation..
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The quotients are equal because they both go in the same number of times. The second pair of quotients just have an extra 0 at the end which just changes the place value of the number.
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PLA HELP WILL MARK BRAINLEST AND GIVE 100 points
Georgia [21]

Answer:

B) measures of variability

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3 years ago
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shutvik [7]

Answer:

D.) MC≅MC

Step-by-step explanation:

We already know that the hypotenuses are the same (because of that tiny line), so we need the legs (HL: hypotenuse-leg). As we can see in the picture, MC is a shared side of both triangles, and this is also the leg. Option D is correct.

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3 years ago
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finlep [7]

Answer:

remaining cardboard area =  122.5πr²

Step-by-step explanation:

area of original rectangle = length * width                                                                      

                                          =  18r * 8r

                                           =     144r²

  • area of semi circle: \frac{1}{2}πr²

Here we have 3 semi circles with radius 3r:

  • area of 3 semi circles:  3( \frac{1}{2} * π * (3r)²)

                                   : 3( \frac{1}{2} * π * 9r²)

                                    : 13.5πr²

  • area of one semi circle with radius 4r:

                       ( \frac{1}{2} * π * (4r)²)

                       ( \frac{1}{2} * π * 16r²)

                             8πr²

  • So the area of remaining cardboard:

            area of rectangle - area of 4 semi circles

                        144r² - 13.5πr² - 8πr²

                                122.5πr²

8 0
2 years ago
Can I get some help abs an easy explanation pls
Svetlanka [38]

we are given the following triangles:

We are asked to determine the value of "y". To do that we will use the tangent of 25:

\tan 25=\frac{y}{x}

We solve for "y" by multiplying both sides by "x":

x\tan 25=y

Now, we take the tangent of 15:

\tan 15=\frac{y}{30+x}

Now, we solve for "y" by multiplying both sides by the denominator:

(30+x)\tan 15=y

Now, we set both values of "y" equal, we get:

x\tan 25=(30+x)\tan 15

now, we solve for "x". First, we apply the distributive property on the right side:

x\tan 25=30\tan 15+x\tan 15

Now, we substract

7 0
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