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3 years ago

How can you tell if something can be shown as a ratio or not.

Mathematics

1 answer:

Hoochie [10]3 years ago

3 0

Multiply numerator by denominator
And u will get the answer

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Candice plotted the points (2, 15) and (0, -1) and then drew a line through these two points. What is the slope of the line she

FrozenT [24]

Use the slope equation: $\frac{y2-y1}{x2-x1}$

Plug in the points (2, 15) and (0, -1).
$\frac{-1-15}{0-2}$ ⇒ $\frac{-16}{-2}$ = 8

The slope of the line is 8.

7 0

2 years ago

Help! Please! Geometry!!

DiKsa [7]

By the Segment Addition Postulate, SAP, we have

XY + YZ = XZ

YZ = XZ - XY = 5 cm - 2 cm = 3 cm

10.

M is the midpoint of XZ=5 cm so

XM = 5 cm / 2 = 2.5 cm

11.

XY + YM = XM

YM = XM - XY = 2.5 cm - 2 cm = 0.5 cm

12.

The midpoint is just the average of the coordinate A(-3,2), B(5,-4)

$M = (A+B)/2 = \left( \dfrac{-3 + 5}{2}, \dfrac{2 + -4}{2} \right)$

Answer: M is (1,-1)

You'll have to plot it yourself.

13.

For distances we calculate hypotenuses of a right triangle using the distnace formula or the Pythagorean Theorem.

$AB^2 =(5 - -3)^2 + (-4 - 2)^2 = 8^2 + 6^2 = 100$

Answer: AB=10

M is the midpoint of AB so

Answer: AM=MB=5

14.

B is the midpoint of AC. We have A(-3,2), B(5,-4)

B = (A+C)/2

2B = A + C

C = 2B - A

C = ( 2(5) - -3, 2(-4) - 2 ) = (13, -10)

Check the midpoint of AC:

(A+C)/2 = ( (-3 + 13)/2, (2 + -10)/2 ) = (5, -4) = B, good

Answer: C is (13, -10)

Again I'll leave the plotting to you.

5 0

3 years ago

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about the

insens350 [35]

Answer:

So, the volume V is

$V=\frac{14\pi}{3}$

Step-by-step explanation:

We have that:

$y=7x\\\\y=0\\\\x=1\\\\x=-4\\$

We have the formula:

$V=2\pi\int_a^b x(g(x)-f(x))\, dx\\\\g(x)>f(x).$

We calculate the volume V, we get

$V=2\pi\int_a^b x(g(x)-f(x))\, dx\\\\V=2\pi\int_0^1 x(7x-0)\, dx\\\\V=2\pi\int_0^1 7x^2\, dx\\\\V=2\pi\cdot 7\left[\frac{x^3}{3}\right]_0^1\\\\V=14\pi\left(\frac{1}{3}-\frac{0}{3}\right)\\\\V=\frac{14\pi}{3}$