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Serjik [45]
3 years ago
15

What differentiates baseline activities from health-enhancing activities?

Physics
2 answers:
gizmo_the_mogwai [7]3 years ago
8 0
The main difference between baseline activities and health-enhancing activities is that baseline activities maintain the status quo, while health-enhancing activities make things better.
earnstyle [38]3 years ago
8 0

Answer:

The difference between reference activities and activities that improve health is the intensity of each one.

Explanation:

Hello! Let's solve this!

Reference activities are activities that do not improve health and have low intensity. For example, walk slowly or stand.

On the other hand, activities that improve health are high intensity activities.

The difference between reference activities and activities that improve health is the intensity of each one.

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A ball with a mass of 0.5 kg is attached to one end of a light rod that is 0.5 m long. The other end of the rod is loosely pinne
prohojiy [21]

Answer:

The tension in the rod as the ball moves through the bottom circle is 9.8 N

Explanation:

When the ball is released from rest, the centripetal force equals the weight of the ball. So mv²/r = mg where m = mass of ball = 0.5 kg, v = speed of ball, r = radius of vertical circle = length of rod = 0.5 m and g = acceleration due to gravity = 9.8 m/s²

v = √gr = √9.8 m/s² × 0.5 m = √4.9 = 2.21 m/s

Now at the bottom of the circle T - mg = mv²/r where T = tension in the rod

T = m(g + v²/r)

= m(g + (√gr)²/r)

= m(g+ gr/r)

= m(g + g)

= 2mg

= 2 × 0.5 kg × 9.8 m/s²

= 9.8 N

So, the tension in the rod as the ball moves through the bottom circle is 9.8 N

8 0
4 years ago
Can someone help me please? I am stuck.
Mars2501 [29]

The distance traveled and the time it takes to travel are both going up at a steady rate. The distance goes from lap 1, lap 2, lap 3, lap 4. The time is increasing by a minute each time. When both the x and y scenario are increasing at a STEADY RATE the line will be linear. B displays a linear line.

8 0
4 years ago
Condition necessary for thermodynamic equilibrium​
dlinn [17]

Answer:

For a thermodynamic system to be in equilibrium, all intensive (temperature, pressure) and extensive thermodynamic properties (U, G, A, H, S, etc) must be constants. Hence, the total change in any of those properties (dℑ ) must be zero at equilibrium.

Explanation:

<em>hope </em><em>it </em><em>helps </em><em>:</em><em>)</em>

8 0
2 years ago
Read 2 more answers
Two resistors of resistances R1 and R2, with R2&gt;R1, are connected to a voltage source with voltage V0. When the resistors are
drek231 [11]

Answer:

r=0.127

Explanation:

When  connected in series

Current = I

When connected in parallel

Current = 10 I

We know that equivalent resistance

in parallel  R= R₁R₂/(R₂+ R₁)

In series  R = R₁+R₂

Given that voltage is constant (Vo)

We also know that relationship between voltage ,current and resistance  

V = I R

Vo = I (R₁+R₂)  ------------1

Vo = 10 I (R₁R₂/(R₂+ R₁)) -------2

From above equations

10 I (R₁R₂/(R₂+ R₁)) = I (R₁+R₂)  

10  R₁R₂ =  (R₁+R₂) (R₂+ R₁)

10  R₁R₂  = 2  R₁R₂  + R₁² + R₂²

8 R₁R₂  =     R₁² + R₂²

Given that

r =  R₁/R₂

Divides by R₂²

8R₁/R₂  = ( R₁/R₂)²+ 1

8 r = r ² + 1

r ² - 8 r+ 1 =0  

r= 0.127 and r= 7.87

But given that R₂>R₁  It means that r<1 only.

So the answer is r=0.127

8 0
3 years ago
What are radio isotopes
sweet [91]
Radioisotopes is a atom with unstable nuclei. They also decay to change different from the electrons over time.
Hope it helped you.
-Charlie
6 0
4 years ago
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