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Whitepunk [10]
3 years ago
10

Which technique(s) are appropriate to completely factor the expression? A) Factor as a difference of squares. B) Factor out the

greatest common factor. C) Factor out the greatest common factor; then factor the difference of squares. D) Factor out the greatest common factor; then factor the perfect square trinomial​
Physics
1 answer:
Ilya [14]3 years ago
4 0

Answer:

The greatest common factor (GCF) is the greatest factor that is common to two or more numbers (they share it). The greatest common factor of two (or more) numbers is the product of all the prime factors the numbers have in common.

Explanation:

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Imagine our Solar System is moving in the Milky Way towards a group of two stars. Star A is a Red star that is slightly closer t
Juliette [100K]

Answer:

None of the stars give of light that is red-shifted

Explanation:

Motion of the observer or the source will cause a change in the wavelength of a wave. This is known as the Doppler effect. When an object and observer are getting close, blue shift occurs i.e., the wavelength gets shorter. When an object and observer are getting farther red shift occurs i.e., the wavelength gets longer.

Here, both the stars are getting closer to us so blue shift will occur.

6 0
3 years ago
Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that
kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.    

 

Explanation:

The Young's modulus is given by:

E = \frac{FL_{0}}{A\Delta L}

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

F = T_{w} = W_{o}

Where:

T_{w}: is the tension of the wire

W_{o}: is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

F = mg = 1700 kg*9.81 m/s^{2} = 16677 N

Hence, the Young's modulus is:

E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa          

Therefore, Young's modulus for the rope material is 20.8 MPa.                

I hope it helps you!                                    

7 0
3 years ago
A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?
Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

m=25/4

m=6.25kg

3 0
3 years ago
The question are in the picture plz help
Tanzania [10]
3) The force of Gravity no longer works, aka you lose gravity.
4) What are the ideas? I can't see them.
4 0
4 years ago
A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v
kumpel [21]
Opposite from the angle is 134.7905

Adjacent to the angle is 192.5007
6 0
4 years ago
Read 2 more answers
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