Answer:
Hiya there!
Step-by-step explanation:
I'm pretty sure that its 80.
Answer:
-1.5
Step-by-step explanation:
Answer:

Step-by-step explanation:

Answer:
Option (B)
Step-by-step explanation:
To calculate the distance between C2 and SW1 we will use the formula of distance between two points
and
.
d = 
Coordinates representing positions of C2 and SW1 are (2, 2) and (-6, -7) respectively.
By substituting these coordinates in the formula,
Distance between these points = 
= 
=
units
Therefore, Option (B) will be the correct option.
This is a factorial sequence that can be modeled by An = n!. As you may see, the increasing numbers are factorials of 1,2,3,4, and 5. Factorial means multiplying backwards and is represented by !. For example, 1! is 1*1 =1. 2! is 2*1, 3! is 3*2*1, 4! is 4*3*2*1 etc.