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enot [183]
3 years ago
15

What are the answers to 2 and 4

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0
They want the numbers ?
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Having trouble with these questions, please help.
12345 [234]
The Empirical Rule affirm:

99.7 % random variable values are between
±
three standard deviation.

95 % random variable values are between
±
two standard deviation.

68 % random variable values are between
±
one standard deviation. There you go!
7 0
2 years ago
Read 2 more answers
The algebraic expression 4x2 + 3Vx+5 is a polynomial
Mila [183]

Answer:

In this problem, I can not tell what is V, so I will answer it in a general way.

A polynomial is something of the form:

a*x^5 + b*x^4 + c*x^3 + d*x^2 + e*x + f

a, b, c, d, e, and f are real numbers and constant.

Where the degree of the polynomial is equal to the greatest power (in this case 5).

You write:

4x^2 + 3Vx + 5

Now, if V is a real number, then we have that this is a polynomial of degree 2.

Because we can write this as:

4*x^2 + (3V)*x + 5

So the answer is true.

Now, if V is a variable or an operation, the answer will be false.

4 0
3 years ago
Help plsssssssssssssssss<br><br><br><br> brainless will be given
Tpy6a [65]

Answer:

Hell earn 2 bucks join one year

7 0
3 years ago
Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to
MrRissso [65]

Answer:

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

\mu=0.375\\\\\sigma^2=0.347

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

p=3/40=0.075

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

P(k=5)=\binom{5}{1}p^1(1-p)^4=5*0.075*0.925^4=0.275

b) The mean and variance of defective components in the sample is:

\mu=np=5*0.075=0.375\\\\\sigma^2=npq=5*0.075*0.925=0.347

The Chebyschev's inequality established:

P(|X-\mu|\geq k\sigma)\leq \frac{1}{k^2}

6 0
3 years ago
Find the center and radius of the circle with the equation:
denpristay [2]

Answer:

It’s 14

Step-by-step explanation:

Just add

6 0
2 years ago
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