Let s represent the measure of the second angle.
The measure of the first angle is 15° less than the second, so we can represent the first angle by (s-15).
The measure of the third angle is 45° more than half the second, so we can represent the third angle by (45+(s/2)).
The sum of these angles is 180°, so we can represent the sum as
... (s-15) + s + (45+s/2) = 180
Collecting terms, we have
... 2.5s +30 = 180
... 2.5s = 150 . . . . . . subtract 30
... s = 150/2.5 = 60 . . . . divide by the coefficient of s
The first angle is 60-15 = 45.
The second angle is 60.
The third angle is 45+60/2 = 75.
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<u>Check</u>
The sum of the three angles is 45 +60 +75 = 180.
Answer:
x = +-sqrt(3) and they are the actual solutions
Step-by-step explanation:
x^2/ (2x-6) = 9/(6x-18)
get a common denominator of 6x-18
x^2/ (2x-6) * 3/3 = 9/(6x-18)
3x^2/ (6x-18) = 9/(6x-18)
since the denominators are the same, the numerators must be the same
3x^2 = 9
divide by 3 on each side
x^2 = 3
take the square root of each side
sqrt(x^2) = +-sqrt(3)
x = +-sqrt(3)
