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2 years ago

Which expression shows the result of applying the distributive property to 3(2x−6)3(2x−6) ?

1 answer:

6 0

Here is the answer. Given 3(2x−6) 3(2x−6), what we need to do is multiply 3 by 2x and -6 and this will give us this result. 6x-18 6x-18. Therefore, the answer for this is the first option. The expression that shows the result of applying the distributive property to 3(2x−6)3(2x−6) is 6x-18 6x-18.

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The Hughes purchased a new condo for $ 1,000,000. at 8 % for 30 years. What is the monthly payment?

viktelen [127]

We know that

P = A/D
Where,
P = monthly payments,
A = Total amount =$1,000,000
$D=[(1+r/12) ^{12*t}-1]/[(r/12)*(1+r/12)^{12*t}]$

in this problem

t=30 years
r=8%----> 0.08

$D=[(1+0.08/12) ^{12*30}-1]/[(0.08/12)*(1+0.08/12)^{12*30}] =136.2835$

$P=1000000/136.2835-----\ \textgreater \ P=$7337.65$

the answer is
$7337.65

4 0

3 years ago

In ten-pin bowling, the highest possible score in a single game is 300.

Natali [406]

Answer:

a) Is it possible for Fred to accomplish this? Yes

b) If it is possible, what score does he need in his next game? 293

Step-by-step explanation:

Step 1

Let us represent the number of games Fred bowled to get an average of 177 = X

His total points scored in that game would be

177 × X

= 177X

To achieve an average of 178 for his next game,

The total number of points he scored was 199, hence that is represented as:

178 = 177X + 199/ X + 1

178(X + 1) = 177X + 199

178X + 178 = 177X + 199

178X - 177X = 199 - 178

X = 21

Hence, Fred bowled 21 games to achieve an average of 178

Therefore, the score he needs to have on the 23rd game is obtained as:

= (23 × 183) - (22 × 178) = 4209 - 3916 = 293

Therefore, it is possible for Fred to raise his average from 178 to 183 in a single game, but he must bowl 293 in his next game to do this.

5 0

3 years ago

In the diagram of O, m∠JOK = 60° and OJ = 6 in. What is the exact area of the shaded region?

Sophie [7]

Answer: 6π

Step-by-step explanation:

Area of a circle is π r².

Area of a section of a circle is π r² × the section of the circle.

$A=\pi r^2\bigg(\dfrac{\theta}{360^o}\bigg)$

Given: r = 6, Ф = 60°

$A=\pi (6)^2\bigg(\dfrac{60^o}{360^o}\bigg)\\\\\\.\quad =\pi (6)^2\bigg(\dfrac{1}{6}\bigg)\\\\\\.\quad =6\pi$

3 0

2 years ago

Find the area of the figure. help asap!

Alborosie

165

5x5= 25
12x12=144
25+144= 165

4 0

3 years ago

Read 2 more answers

What is the midpoint of a segment whose endpoints are (-5,6) and (-7,2)?

zloy xaker [14]

The answer to the question is b

5 0

3 years ago