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solmaris [256]
3 years ago
14

D=rt for t Solve the equation

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

Answer:

d = r * t

t = d / r

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Can someone read this Algebra help please
lilavasa [31]
That means 2*3* the sum of 5+8 which gives you 78 as your answer. Hope this helps and please select as the brainliest answer.
3 0
3 years ago
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Which function is an odd function?
Mrac [35]

Answer:

Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f. A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

Step-by-step explanation:

7 0
4 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
4 years ago
Determine the numerical length of JK.​
Zarrin [17]

Answer:

30

So the two sectors add to the full length:

JK + IJ = IK

x+6 + 9 = 2x

Rearrange:

x=15

So the numerical length:

2x

2*15

30

5 0
3 years ago
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PLEASE HELP ME!! Kevin earns a base salary of $350.00 every week with an additional 12%
Mrrafil [7]
<h3>Answer:  944 dollars for the week</h3>

============================================================

Explanation:

He sold $4950 worth of items. Take 12% of this amount to get

12% of 4950 = 0.12*4950 = 594

So he earns $594 in commission on top of the $350 base salary paid every week. In total, he earns 594+350 = 944 dollars for that week

This isn't the per week pay because he would need to sell exactly $4950 worth of goods each week to keep this same weekly pay.

5 0
3 years ago
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