For this case we have the following equation:
We must find the value of "x":
We apply cube root on both sides of the equation to eliminate the exponent:
![x = \sqrt [3] {375}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D)
We can write 375 as 
So:
![x = \sqrt [3] {5 ^ 3 * 3}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B5%20%5E%203%20%2A%203%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Then, the correct options are:
![x = \sqrt [3] {375}\\x = 5 \sqrt [3] {3}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B375%7D%5C%5Cx%20%3D%205%20%5Csqrt%20%5B3%5D%20%7B3%7D)
Answer:
Option A and B
.875 seconds
a=360t
b=280t+(280*.25)
360t=280t+(280*.25)
360t=280t+70
80t=70
t=.875
180-this number or 360 because its a circumference
Answer:
2 1/6
Step-by-step explanation:
Because the denominators are different, and there are whole numbers involved, then first make the fractions improper.
4 1/2 -> 9/2
6 2/3 -> 20/3
Next, make the denominators the same by multiplying each fraction by the denominator of the other.
9/2 * 3 = 27/6
20/3 * 2 = 40/6
Then you can subtract the numerators because the denominators are the same:
40/6-27/6= 13/6
Then you can convert to a mixed fraction if need be.
2/5 more i believe!
basically just subtract 4/5 and 2/5 and you get 2/5
feel free to mark brainliest, hope this helps!
