Hello here is a solution :
x²-8y-6x+y²=4....(1)
A)
x²-6x = x²-2(3)x+9-9
= x²-2(3)x+3²-9
x²-6x =(x-3)² -9
B)
y²-8y = y²-2(4)y +4²-16
y²-8y = (y-4)²-16
C)
in (1) :
(x-3)² -9 +(y-4)²-16 = 4
(x-3)² +(y-4)² = 29 ...<span>is the standard form of the equation
</span> <span>Select answer 1 :
</span><span>A: 3
B: 4
C: (x−3)2+(y−4)2=29</span>
I think that the Equivalent fraction is 6/8
<h3>Yes, this is true.</h3>
To be considered similar triangles, the angles must be the exact same, and the sides must be proportional. The side lengths do not have to be exactly the same, but they must be proportional (like a ratio, suppose one triangle has a side length of 1, and the similar triangle has a side length of 3. The ratio is 1:3, and all sides will follow this ratio.)
Answer:
y = 4x - 1
Step-by-step explanation:
Just plug it into slope intercept form which is y = mx + b
hope this helped!
Answer:
The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.
Step-by-step explanation:
To solve this question, we use the central limit theorem.
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
In this problem, we have that:
The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.
