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AysviL [449]
3 years ago
7

Ghani is going to use these instructions to make a fizzy drink instruction: mix 5 parts of lime juice with 3 parts of lemonade g

hani thinks thats he has 300ml of lime juice and 200ml of lemonade if he is correct what is the greatest amount of fizzy drink can he make?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
6 0

Answer: 480 ml

The greatest amount of fizzy drink can he make is 480 ml

Step-by-step explanation:

Given;

Mixing ratio = 5 : 3

Volume of lime juice = 300ml

Volume of lemonade = 200ml

From the given ratio;

5 ml of lemon juice needs 3 ml of lemonade to make 8 ml of fizzy drink.

Assuming all the lemon juice were used;

For 300ml of lemon juice,

It'll require 300/5 × 3 ml of lemonade.

Volume of lemonade needed V2= 300/5 × 3 = 180 ml

Volume of fizzy drink = volume of lemon juice + volume of lemonade

Volume of fizzy drink = 300ml + 180ml = 480ml

The greatest amount of fizzy drink can he make is 480 ml

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See attachment.

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Find the new price for the markdown given. Round to the nearest cent if necessary.
algol13

Answer:

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Step-by-step explanation:

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3 years ago
Sharon runs a day care center. Of the last 10 children to enroll at the day care center, 4 of them have been preschoolers. What
JulijaS [17]

Answer:

The experimental probability that the next child to enroll will be a preschooler is 40%

P(E) = 40%

Step-by-step explanation:

What is Experimental Probability?

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In this problem we are given that out of the last 10 children to enroll at the day care center, there are 4 children who belong to the category of preschoolers.

We are asked to find the experimental probability that the next child to enroll will be a preschooler.

The required experimental probability is given by

P(E) = \frac{\text{number \:of \:desired \:outcomes}}{\text{total \:number \:of \:outcomes}}

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P(E) = \frac{4}{10} \\\\P(E) = 0.40\\\\P(E) = 40\% \\\\

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