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3 years ago

What is the greatest common factor of 18 and 54?

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

Answer:

Step-by-step explanation:

18=2×3×3

54=2×3×3×3

gcd=2×3×3=18

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Evaluate v(x) = 14-3x when x=-3, 0 and 4.

PtichkaEL [24]

Answer:

$v(-3)=23\\v(0)=14\\v(4)=2$

Step-by-step explanation:

$v(x)=14-3x$

$v(-3)=14-3(-3)\\\\v(-3)=14-(-9)\\\\v(-3)=23$

$v(0)=14-3(0)\\\\v(0)=14-0\\\\v(0)=14$

$v(4)=14-3(4)\\\\v(4)=14-12\\\\v(4)=2$

5 0

3 years ago

Read 2 more answers

Without measuring, how can you determine whether two sides of a polygon are congruent?

Alinara [238K]

Ow... this geometry is sure hard!!
.
Wait a second. Nope.
.
TWO SIDES!!
.
ITT!!
.
CONVERSE ITT!!
.
Converse Isosceles Triangle Theorem!
.
Look at the picture I attached.
.
Two angles equal... THE SIDES ADJACENT TO IT EQUAL!!
.
PERFECTO!!
.
Hope I helped!!

Source: I am learning Honors Geometry, near end of course.

7 0

3 years ago

CAN SOMEONE HELP MEEEEEEEEEE

Debora [2.8K]

Answer:

$c = \sqrt{146} \\ x = 48°$

5 0

3 years ago

The simple interest on a sum of money for 2 years at 12% per annum is rupees 1380

julia-pushkina [17]

Answer:

5750

710.7

Step-by-step explanation:

Simple interest = principal. * rate * time

Principal (p) = sum of money

1380 = p * 0.12 * 2

1380 = 0.24p

p = 1380 / 0.24

p = 5750 rupees.

The compound interest :

A = P(1 + r/n)^nt

A = final amount

n = number of compounding times per period

t = period

A = 5750(1 + 0.12/2)^2*1

A = 5750(1 + 0.06)^2

A = 5750(1.06)^2

A = 5750 * 1.1236

A = 6460.7

Hence, compound interest is :

Final amount - principal

6460.7 - 5750

= 710.7 rupees

4 0

3 years ago

Sara is 9 years younger than her brother, Michael. The sum of their ages is 47 years. How old is Sara and how old is her brother

kotykmax [81]

Answer:

Michael is 38 and Sara is 29

Step-by-step explanation:

Because it says the sum of their age is 47 you do 47-9=38 so that would be Michael's age and than because Sara is 9 years younger than him and then you would do 38-9=29

7 0

3 years ago