Write the equation of the graphed function. A. y = 5⁄4x + 3 B. y = 4⁄5x + 3 C. y = 4⁄5x – 3 D. y = 5⁄4x

You're playing a game where you defend your village from an orc invasion. There are 3 characters (elf, hobbit, or human) and 5 d

Airida [17]

1/15

1/3 chance of getting elf, 1/5 chance of getting magic so the chance of getting both is 1/3x1/5=1/15

3 0

3 years ago

Statement: 2x-3>7 which is greater? 5 or x

kap26 [50]

X is greater with respect to the statement because x will have to be greater than 5 for the statement to be true

3 0

3 years ago

Read 2 more answers

What is the value of X?<br> A 57 B 48 C 38 D 28

olga_2 [115]

Answer: D. 28

Step-by-step explanation:

The 3 interior angles of a triangle always add up to 180

Soooo:

95 + 57 = 152

180 - 152 = 28

5 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

ANSWER ASAP ITS FOR FINALS

Roman55 [17]

Answer:

9. 66°

10. 44°

11. $2\sqrt{7}$

12. $2\sqrt{3}$

13. 27.3

14. 33.9

15. 22°

16. 24°

Step-by-step explanation:

9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:

120 + 80 = 200

360 - 200 = 160

12(5) + 6 = 66°

19(5) - 1 = 94°

94 + 66 = 160

10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:

68 x 2 = 136

180 - 136 = 44

11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:

a² + b² = c²

a² + 6² = 8²

a² + 36 = 64

a² = 28

a = $\sqrt{28}$

a = $2\sqrt{7}$

12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:

a² + b² = c²

a² + 2² = 4²

a² + 4 = 16

a² = 12

a = $\sqrt{12}$

a = $2\sqrt{3}$

13. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #13, write:

Sin(47°) = $\frac{20}{x}$

x = 27.3

14. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #14, write:

Tan(62°) = $\frac{x}{18}$

x = 33.9

15. Use SOH CAH TOA and solve with a scientific calculator. For shown work on #15, write:

cos(θ) = 52/56

θ = cos^-1 (0.93)

θ = 22°

16. (Same steps as #15) Use SOH CAH TOA and solve with a scientific calculator. For shown work on #16, write:

sin(θ) = 4/10

θ = sin^-1 (0.4)

θ = 24°

Good luck!!

8 0

2 years ago

Write the equation of the graphed function. A. y = 5⁄4x + 3 B. y = 4⁄5x + 3 C. y = 4⁄5x – 3 D. y = 5⁄4x – 3